Answer:
One side is more positive, the other is more negative
Explanation:
When an atom is electrically polarized, it means that one side has more electrons than the other. This makes one side more negative as it has more electrons than the other. I hope this helps!
The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 *
m/s
Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.
By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.
given
charge of electron = 1.6 ×
C
mass of electron = 9.1 ×
kg
Force in an electric field = q*E
potential energy is stored in the form of work done
potential energy = work done = Force * displacement
= q * (E * d)
= q * (V) = 1.6 ×
* 100
stored potential energy = kinetic energy in electric field
kinetic energy = 1/2 * m * 
= 1/2 * 9.1 ×
* 
equation both the equations
1/2 * 9.1 ×
*
= 1.6 ×
= 0.352 *
m/s
= 35.2 * 
= 5.93 *
m/s
To learn more about kinetic energy in electric field here
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The proper difference between hor Rse and horse is both shows the same thing that is the horse
A) 5 kg block of wood
B) 100 kg person
C) 412 kg motorcycle
D) 2540 kg elephant
Answer: D
Answer:
A_resulting = 0.2 m
Explanation:
Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.
With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is
A_res = 2A
A_resultant = 2 .01
A_resulting = 0.2 m