Try clicking the down arrow on the search bar or right clicking it and selecting an option no if that doesn’t work then drag the || to somewhere or right click it. If none of those work you can right click the taskbar and see if there is anything that looks like it could be the search bear and uncheck it
Answer:
The program in Python is as follows:
word = input("Word: ")
if len(word) < 5:
print("At least 5 characters")
else:
pal = word[0:5]
word = word[0:4]
word = word[::-1]
pal+=word
print(pal)
Explanation:
This gets the word from the user
word = input("Word: ")
This checks if the length of the word is less than 5.
if len(word) < 5:
If yes, this tells the user that at least 5 characters is needed
print("At least 5 characters")
If otherwise
else:
This extracts the first 5 characters of the word into variable named pal
pal = word[0:5]
This extracts the first 5 characters of the word into variable named word
word = word[0:4]
This reverses variable word
word = word[::-1]
This concatenates pal and word
pal+=word
This prints the generated palindrome
print(pal)
Answer:
Check the explanation
Explanation:
// include the necessary packages
import java.io.*;
import java.util.*;
// Declare a class
public class DataReader
{
// Start the main method.
public static void main(String[] args)
{
// create the object of scanner class.
Scanner scan = new Scanner(System.in);
// Declare variables.
boolean done = false;
boolean done1 = false;
float sum = 0;
double v;
int count = 0;
// start the while loop
while (!done1)
{
// start the do while loop
do
{
// prompt the user to enter the value.
System.out.println("Value:");
// start the try block
try
{
// input number
v = scan.nextDouble();
// calculate the sum
sum = (float) (sum + v);
}
// start the catch block
catch (Exception nfe)
{
// input a character variable(\n)
String ch = scan.nextLine();
// display the statement.
System.out.println(
"Input Error. Try again.");
// count the value.
count++;
break;
}
}
// end do while loop
while (!done);
// Check whether the value of count
// greater than 2 or not.
if (count >= 2)
{
// display the statement on console.
System.out.println("Sum: " + sum);
done1 = true;
}
}
}
}
Sample Output:
Value:
12
Value:
12
Value:
ten
Input Error. Try again.
Value:
5
Value:
nine
Input Error. Try again.
Sum: 29.0
Answer:
Correct Answer is (d) Information sensitivity policy
Explanation:
Information sensitivity policy establishes the criteria for classifying and securing the organization's information in a manner that is appropriate to its level of security.
However, other options are incorrect. Server security can be established only on servers and on information/data that is in the server from unauthorized access. While VPN security is used for protecting network and encryption is used to encrypt data from illegal access.
However, only information sensitivity policy is used for classifying and securing organization information to the outside world.
The intention of information sensitivity policy:
The intention of using any information sensitivity policy is to help the employee to determine what information can be disclosed to non-employee, as well as the relative sensitivity of the information that should not be disclosed outside of the company without proper permission or authorization from supreme leadership of an organization.
