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alekssr [168]
3 years ago
12

Plz i NEED HELP ABOUT TO FINISH THIS CLASS! PLZ

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

last one

Step-by-step explanation:

GrogVix [38]3 years ago
3 0
The last one quick quick
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What's the lateral area of the following cone?​
Kay [80]

Answer:

Since the base of a cone is a circle, we substitute 2πr for p and πr2 for B where r is the radius of the base of the cylinder. So, the formula for the lateral surface area of a right cone is L. S. A=πrl , where l is the slant height of the cone .

Step-by-step explanation:

I tired??? sorry if it's wrong???

7 0
3 years ago
The tour bus had 60 passengers. The survey showed that 20% of the passengers enjoyed the tour. How many passengers enjoyed the t
aleksklad [387]
The answer is D. My dad taught me an easy way to solve those kind of problems.You need to do (60×20)÷100. And since 60 and 20 both have a zero and 100 has 2 zeros, u can cross out all the zeros and just do 6×2 and divide that by 1 and so 20% of 60 is 12. Hope this helped :)
5 0
3 years ago
I really need help with this and if you don't know it says which one is NOT
Natasha_Volkova [10]
The fourth one I think
3 0
3 years ago
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What is the answer to this?
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4 0
3 years ago
5.b) If z^(1/2)=x^(1/2)+y^(1/2) , show that (x+y-z)^2=4xy
Rudik [331]

Answer:

Step-by-step explanation:

  • (x+y-z)²= 4xy
  • (x+y-z)²- 4xy = 0
  • (x+y-z)²-(2√x√y)² = 0
  • (x+y-z-2√x√y)(x+y-z+2√x√y) =0
  • [(√x-√y)²-z]*[(√x+√y)²-z]=0
  • (√x-√y)²-z = 0 or (√x+√y)²-z = 0

We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²

  • so (√x+√y)²-z = 0

so (x+y-z)²= 4xy

3 0
3 years ago
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