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3 years ago

Plz i NEED HELP ABOUT TO FINISH THIS CLASS! PLZ

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

last one

Step-by-step explanation:

GrogVix [38]3 years ago

3 0

The last one quick quick

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True/False: All 3 angles of an equilateral triangle measure 60 degrees.<br> True<br> False

Ber [7]

Answer:

true

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLEASE HELP FAST!!

Mice21 [21]

Answer:

367.6 m

Step-by-step explanation:

Use trigonometry

<u>Let the height of the cloud be x, then we have:</u>

tan 35° = x/525
x = 525 tan 35°
x = 367.6 (rounded)

The height of the cloud layer is 367.6 m

8 0

3 years ago

A fitness center is interested in the average amount of time a client exercises in the center each week. Define the following in

Lubov Fominskaja [6]

Answer: C

Step-by-step explanation: As they are interested in the amount of time a client exercises in a week, the population would be all the clients that use the fitness center for a given week.

Clients that do not go on this week are not part of the population. The amount of time is what they want to know, so it cannot be the population.

7 0

3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

4 years ago

What is equivalent to 1 ½ meters

frosja888 [35]

1 5/10 meters is equivalent

6 0

3 years ago