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laiz [17]
3 years ago
6

A given set of values is found to be a normal distribution with a mean of 140 and a standard deviation of 18.0. Find the value t

hat is greater than 45% of the data values.
Mathematics
2 answers:
Andreyy893 years ago
6 0

Answer:

Formula for Z score

Z=\frac{X-B}{A}

Where, Z is Z score for value that is greater than 45% of the data values.

X=Score=?

B=Mean =140

Standard Deviation = 18

Z score for value above 45 % of data set = 0.9987 - 0.0668=0.9319

Z_{45 percent above}=Z_{100}-Z_{45}=0.9987-0.0668=0.9319\\\\0.9319=\frac{X-140}{18}\\\\ 0.9319*18=X-140\\\\X=140 +16.7742\\\\ X=156.7742

X score for value that is greater than 45% of the data values.= 156.78 (Approx)

Alisiya [41]3 years ago
5 0

Answer:

The value that is greater than 45% of the data values is approximately 137.84.

Step-by-step explanation:

The key is transforming values from this distribution to a z-score range and finding the corresponding value using a z-score table.

We are looking for a value x which attains a critical z-score that corresponds to the (100-45)%=55-th percentile:

z_{0.55} = \frac{x-\mu}{\sigma}=\frac{x-140}{18}\implies x = 18\cdot z_{0.55}+140

The critical z value (from z-score table, online) is: -0.12, so:

x = 18\cdot z_{0.55}+140=18\cdot(-0.12)+140\approx137.84

The value that is greater than 45% of the data values is approximately 137.84.


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Answer:

12 red balls

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2 blue balls

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Step-by-step explanation:

set no. of yellow, blue, red and green ball as y, b, r, g respectively

y=2b

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2b + b + 3(2b) + b = 20

10b = 20

b =2

y = 4, r = 12, b =2, g =2

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6 0
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3 years ago
Of 10 girls in a class, three have blue eyes. Two of the girls are chosen at random. Find the probability that: (a) both have bl
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C.

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8 0
3 years ago
What is 3 × 100 + 3 × 1 + 4 ×( 1/10) + 5 ×( 1/100) + 7 ×(1/1000) ?
Natalka [10]
The answer is:  [B]:  " 303.457 " .________________________________________
Explanation:  Use the "order of operations"; which is represented by the mnemonic device:

PE MD AS ;  (Please excuse my dear Aunt Sally/Susan);

also, known as:  BE MD AS ;  (Be excused, my dear Aunt Sally/Susan);

The operations performed are done in order of first to last;  the "P" stands for parentheses" ;  The "B" stands for "brackets".

The "MD" stands for "multiplication, then division";  As per the mnemonic device, there should be an "arrow from left to right over the "MD" ; which means that when both Multiplication AND division occurs; the operations are perform in order from left to right, as they occur in the problem being solved.

The "AS" stands for "addition, then subtraction".  Again, as per the mnemonic device, there should be an "arrow from left to right over the "AS" ; which means that when both addition AND subtraction occurs; the operations are perform in order from left to right, as they occur in the problem being solved.
___________________________________________________________
We are given: 
_________________________
3 × 100 + 3 × 1 + 4 ×( 1/10) + 5 ×( 1/100) + 7 ×(1/1000) ?
___________________________________________
 Using the "order of operations" ;  we can rewrite this problem as:

(3*100) + (3*1) + [ 4*(1/10) ]  + [5*(1/100) + [7*(1/1000)] ;

Note that both multiplication and division take priority over addition, according to the "order of operations".
_______________________________________________
Now, rewrite:  300 + 3 + (4/10) + (5/100) + (7/1000).
_______________________________________________
Change the "(4/10)"  to:   ?/ 1000 ;  "4/10" = (4*100)/(10*100) = 400/1000 ;

Change the "(5/100)" to:  ?/1000 ;  "5/10" = (5*10)/(100*10) = 50/1000  ;

____________________________
Now, rewrite:   300 + 3 + (4/10) + (5/100) + (7/1000) =

            300 + 3 + (400/1000) + (50/1000) + (7/1000) =

            303 + [ (400 + 50 + 7) / 1000 =    303 + (457/ 1000) ;

                                                          =  303.457 ;
                                                   which is:  Answer choice:  [B].
_______________________________________________________
4 0
3 years ago
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