Answer:
A. 
Step-by-step explanation:
![\dfrac{\sqrt[3]{6}}{\sqrt[4]{6}} = 6^{\frac{1}{3} - \frac{1}{4}} = 6^{\frac{4}{12} - \frac{3}{12}} = 6^{\frac{1}{12}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B6%7D%7D%7B%5Csqrt%5B4%5D%7B6%7D%7D%20%3D%206%5E%7B%5Cfrac%7B1%7D%7B3%7D%20-%20%5Cfrac%7B1%7D%7B4%7D%7D%20%3D%206%5E%7B%5Cfrac%7B4%7D%7B12%7D%20-%20%5Cfrac%7B3%7D%7B12%7D%7D%20%3D%206%5E%7B%5Cfrac%7B1%7D%7B12%7D%7D)
Answer: A. 
If it’s a slope- intercept form/ y=mx+b then it’s y=1x+0 because each time it goes up one and over one which is 1/1 or 1 whole and the y-intercept is at (3,0) and we use the Y which is 0
The total of the pupils are the 100%, or in fraction mode, 1, the whole, so we have:
bus + car + foot = total
1/3 + car + 3/10 = 1
car = 1 - 3/10 - 1/3
car = 1 - (9/30 + 10/30)
car = 30/30 - 19/30
car = 11/30
that is the fraction that come by car
Answer:
The side length of the large square is √2 times larger than the side length of the small square.
Step-by-step explanation:
Suppose we have a small square (square 1) and a large square (square 2). The area of the large square is twice that of the small square, that is,
A₂ = 2 A₁
A₂/A₁ = 2 [1]
The area of a square is equal to the length of the side (l) raised to the second power.
A = l²
l = √A
The ratio of l₂ to l₁ is:
l₂/l₁ = √A₂ / √A₁ = √(A₂/A₁)
We can replace [1] in the previous expression.
l₂/l₁ = √2
The side length of the large square is √2 times larger than the side length of the small square.