The weight of the third heaviest among the four dogs is 2 kg.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.
Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.
29 + 28 + 2 + 1 = 60 kg
The weight of the third heaviest among the four dogs is 2 kg.
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\left[x \right] = \left[ 6\right][x]=[6] totally answer
Answer:
The answer is 1485 m^2
Step-by-step explanation:
27 per m^2 so 27 times 55 = 1485 m^2
C. It’s goes over two and up three. So therefore L would be (3,2)
Answer:
Step-by-step explanation:
m = (4-1) / (9-5)
m = 3/4