The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)
Substitute eqn 1 in above equation
Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
The factorization of the numbers is obtained as
(a) 36 = 2² x 3²,
(b) 60 = 2² x 3 x 5,
(c) 84 = 2² x 3 x 7,
(d) 99 = 3² x 11 and
(d) 180 = 2² x 3² x 5
<h3>Factor of the numbers</h3>
To factorize the numbers we use their factors as show below;
<h3>Factors of 36</h3>
36 = 2² x 3²
<h3>Factors of 60</h3>
60 = 2² x 3 x 5
<h3>Factors of 84</h3>
84 = 2² x 3 x 7
<h3>Factors of 99</h3>
99 = 3² x 11
<h3>Factors of 180</h3>
180 = 2² x 3² x 5
Thus, the factorization of the numbers is obtained as 36 = 2² x 3², 60 = 2² x 3 x 5, 84 = 2² x 3 x 7, 99 = 3² x 11 and 180 = 2² x 3² x 5.
Learn more about factorization here: brainly.com/question/25829061
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Answer:
i got A
Step-by-step explanation:
Answer:
28 m
Step-by-step explanation:
The longer side can be found using the Law of Cosines. The semi-diagonals are of length 12 and 20 m, and the angle between them facing the long side is 180° -60° = 120°.
c^2 = a^2 +b^2 -2ab·cos(C)
c^2 = 12^2 +20^2 -2·12·20·cos(120°) = 144 +400 +240 = 784
c = √784 = 28
The longer side is 28 meters.
Answer:
its Aor the first option because it has repeated x values making it not a function.
