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Ann [662]
3 years ago
15

You work two jobs. You earn $11.90 per hour as a salesperson and $10.50 per hour stocking shelves. Your combined earnings this m

onth are $178.50. Let x represent the number of hours worked stocking shelves and let y represent the number of hours worked in sales. Graph the equation that models this situation.PLEASE HELP FAST. Graphing is not needed just tell the points, please.
Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
178.50 = 11.90y + 10.50x ⇒ equation in standard form.

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Simplify <br><img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B%20-%20180%7D%20" id="TexFormula1" title=" \sqrt{ - 180} " alt="
QveST [7]

Answer: (6\sqrt{5})i

This is the same as saying 6i\sqrt{5}

====================================================

Work Shown:

\sqrt{-180} = \sqrt{-1*36*5}\\\\\sqrt{-180} = \sqrt{-1}*\sqrt{36}*\sqrt{5}\\\\\sqrt{-180} = i*6*\sqrt{5}\\\\\sqrt{-180} = 6i\sqrt{5}\\\\\sqrt{-180} = (6\sqrt{5})i\\\\

where i = \sqrt{-1}

As the steps show above, the idea is to factor the radicand into smaller pieces where one of those pieces is the largest perfect square possible. In this case, 36 is the largest factor of 180 that's a perfect square. Then I used the rule \sqrt{A*B} = \sqrt{A}*\sqrt{B} to break up the root.

The parenthesis used at the very end is to help separate the 6\sqrt{5} from the i term. The "i" is not under the square root.

4 0
3 years ago
Please help I don’t understand this
horrorfan [7]

Answer:

C) 17

Step-by-step explanation:

Using the rule

A^2 + B^2 = C^2

8^2 + 15^2 = x^2

64 + 225 = x^2

x^2 = 289

x= _/-289

x = 17

3 0
3 years ago
What is the coefficient of the term 53xy ? A. 5 B.1/3 C.5xy D.5/3
svet-max [94.6K]
It is d i did the test and got an a
7 0
3 years ago
I need help with all of them
lara [203]
Click on the picture! This is the explanation in accident I deleted it hope it helps!

6 0
4 years ago
May you guys please help me on this one
NNADVOKAT [17]

Answer:

y maximum is at 1 for both the points (4,1) and (-4,1)

Step-by-step explanation:

5 0
2 years ago
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