GIF would always be greater I'm pretty sure
-41 I think u do distributive property
Answer:
The expected cost is $8.75
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Step-by-step explanation:
Given

--- If Bob and Anna meet
--- If Bob and Anna do not meet
Required
The expected cost of Bob's meal
First, we list out all possible time both Bob and Anna can select
We have:



The outcome of them meeting at the same time is:


The probability of them meeting at the same time is:



The outcome of them not meeting:


The probability of them meeting at the same time is:



The expected cost is then calculated as:



Take LCM



<em>The expected cost is $8.75</em>
There are 16 vegetable plants because 40/5 is 8 and 2 times 8 is 16. 5:2=40:16
Answer:
7777777777777777777777777777777777777777777777777777777777
Step-by-step explanation:
Any number multiplied by 1 is itself.