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3 years ago

Need help now! WRITER: Explain how ferns and fungi are different.

1 answer:

5 0

Fungus aren’t plants

Also this is what I found in the internet: „Ferns are plants. They look quite similar with lichens (e.g. Lobaria sp.) and like fungi, they bear spores underneath the fronds. However, ferns do not get nourishment from decaying matter ( some fungi species does) but undergoes photosynthesis like other plants.“

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How many hydrogen atoms are in water, H2O? A) 1 B) 2 C) 3 D) 0

pishuonlain [190]

There are two hydrogen atoms in one molecule of water.

The answer is B) 2

8 0

3 years ago

Read 2 more answers

What is the density of an object if its mass is 10 g and a volume of 2 mL?

Lilit [14]

Hi there! Let's solve this problem shall we!

⠀Volume = 10g

Mass = 2 mL

In this specific problem, they are asking us to find the density of the object. So, using the information given to us (volume and mass), let's solve the problem!

Now, if you remember, D = M ÷ V

So, let's fill in the blanks!

D = Our unknown value

M = 2mL

V = 10g

Here is the filled out formula:

D = M ÷ V

D = 2mL ÷ 10g

D = 5 g/mL

*Make sure you put the units for your final solution!*

4 0

2 years ago

Which of the following might a chemist choose to study?

Serjik [45]

Answer:

B. Better ways to recycle plastics

Explanation:

A chemist might choose to study better ways to recycle plastics because there may be certain types of chemicals that can disintegrate the plastic..

7 0

3 years ago

What is the ph of a saturated solution of aluminum hydroxide?

sasho [114]

Answer is attached below ( sorry for mistake )

6 0

4 years ago

Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain

RoseWind [281]

Answer:

$M_{per}= 52.86$

$W_{per}=47.14$

Explanation:

First mixture:

40 wt% methanol - 60 wt% water 200 kg

$m_{met1}=200 kg * 0.4= 80 kg$

$m_{wat1}=200 kg * 0.6= 120 kg$

Second mixture:

70 wt% methanol - 30 wt% water 150 kg

$m_{met2}=150 kg * 0.7= 105 kg$

$m_{wat2}=150 kg * 0.3= 45 kg$

Final mixture:

$m_{metF=80 kg + 105 kg= 185 kg$

$m_{watF}=120 kg + 45 = 165 kg$

$M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86$

$W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14$

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0

3 years ago