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Helen [10]
3 years ago
14

What compound is this?

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
7 0

Answer:

Carbon Tetrachloride

Explanation:

1 Carbon atom, 4 chlorine atoms (hence "tetra" prefix)

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A solution labeled "0.105 M NaOH" would contain ______________ moles of NaOH in each liter of solution.
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It would contain 0.105M moles of NaOH in each liter of solution
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A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained. How many
beks73 [17]

<u>Answer: </u>

A sample initially contained 150 mg of radon-222. After 11.4 days only 18.75mg of the radon-222 in the sample remained where 3 half-lives have passed

<u>Explanation:</u>

Given, the initial value of the sample, A_0 = 150mg

Final value of the sample or the quantity left, A = 18.75mg

Time = 11.4 days

The amount left after first half life will be ½.

The number of half-life is calculated by the formula

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where N is the no. of half life

Substituting the values,

\frac{18.75}{150}=\left(\frac{1}{2}\right)^{N}

\left(\frac{1}{2}\right)^{3}=\left(\frac{1}{2}\right)^{N}

On equating, we get, N = 3

Therefore, 3 half-lives have passed.

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PLEASE HELP :-)
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<span>2.6 x 10^-3 = [I]^2 / [I2] = [I]^2 / 0.95 </span>
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<span>Ksp = [Ba2+][CO32-] = ( 1.1 x 10^-4)^2=1.2 x 10^-8</span>
6 0
3 years ago
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