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inessss [21]
3 years ago
6

What's 4 2/5 x 10 in Distributive Property?

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0
Boo just say If it right or not..... sheesh your a smart one but you don't need to rub it in lol
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When finding 433 - 249 using place value. What do you subtract first?
Ksenya-84 [330]
You subtract the ones place, then the tens, and lastly the hundreds place. Your answer will be 184 if you are looking for the answer as well.
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3 years ago
254 divided by 8 with remander no decimal long division
Verdich [7]
I think the answer is 31.75
8 0
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Read 2 more answers
prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0
3 years ago
Given the regular polygon, what is the measure of each numbered angle?​​
ANEK [815]

Answer:

Answer A

Step-by-step explanation:

Approach 1

B, C, and D are wrong because angles 1 and 2 are congruent.

Therefore your answer of both being 60°

Approach 2

Let x = angle 1.

360/x = 6

x = 60°.

Therefore Angle 1 is 60°

An interior angle of a hexagon is 120°

Let y = angle 2.

y is half of 120°

So 120/y = 2

y = 60°

4 0
2 years ago
In a group of 40 people, 27 can speak English and 25 can speak Spanish. How many can speak
Svetradugi [14.3K]

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{Information \: provided \:  with  \: us }}}}}\: \bigstar}

➻ In a group of 40 people, 27 can speak English and 25 can speak Spanish.

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{What \: we \:  have  \: to \: find ? }}}}}\: \bigstar}

➻ The required number of people who can speak both English and Spanish .

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{Assumption}}}}}\: \bigstar}

<u>Consider</u> ,

➻ A → Set of people who speak English.

➻ B → Set of people who speak Spanish

➻ A∩B → Set of people who can speak both English and Spanish

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{Given}}}}}\: \bigstar}

  • ➻ n (A) = 27

  • ➻ n (B) = 25

  • ➻ n (A∪B) = 40

  • ➻ n(A∩B) = ?

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{Now}}}}}\: \bigstar}

➻ n(A∪B) = n(A) + n (B) - n(A∩B)

➻ 40 = 27 + 25 - n (A∩B)

➻ 40 = 52 - n (A∩B)

➻ n (A∩B) = 52 - 40

➻ ∴ n (A∩B) = 12

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{Therefore}}}}}\: \bigstar}

∴ Required Number of persons who can speak both English and Spanish are <u>12 .</u>

━━━━━━━━━━━━━━━━━━━━━━

\qquad {\: \:\bigstar \:  {\underline{\overline{\boxed{\bf{Verification}}}}}\: \bigstar}

➻ n(A∪B) = n(A) + n (B) - n(A∩B)

➻ 40 = 27 + 25 - 12

➻ 40 = 52 - 12

➻ 40 = 40

➻ ∴ L.H.S = R.H.S

━━━━━━━━━━━━━━━━━━━━━━

6 0
2 years ago
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