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vaieri [72.5K]
3 years ago
10

Find the total amount you will pay on a bill of $43.50 and tip rate of 12%.

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0
About $48.72



Explanation:
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A line that includes the point (-3,-4) and (-4,f ) has a slope of 6. What is the value of f?
Eduardwww [97]

Answer:

f = -10

( -3, -4) ( - 4 , -10)

Step-by-step explanation:

Formula for slope

m =( y_2 - y_1)/(x _2 - x _1)

m = 6

6 = (y_2 - y_1) / (x _2 - x_1)

Substitute the points

( -3 , -4) ( -4 , f)

x_1 = -3

y_1 = -4

x_2 = -4

y_2 = f

Insert the values into

6 = (y_2 - y_1) / (x_2 - x_1)

6 = (f - (-4))/ ( -4 - (-3)

6 = ( f + 4)/ ( -4 + 3)

Cross multiply

6 ( -4 + 3) = f + 4

6 ( -1) = f + 4

-6 = f + 4

-6 - 4 = f

f = -6 - 4

f = -10

( -3 , -4) ( -3 , f)

The value of f is -10

( -3 , -4) ( -3 , -10)

8 0
3 years ago
What equation best represents the following sentence?
Tems11 [23]

Answer:

2n + 1 to find the first odd number.

Step-by-step explanation:

that is it

8 0
3 years ago
I must be s.tupid but someone plzzzzzzzz help!
Gala2k [10]

Answer:

=

Step-by-step explanation:

8.5 is also 8 and 1/2, it just has negative signs infront

3 0
3 years ago
find the equations of the tangents to the curve y= x(x-1)(x+2) at the points where the curve cuts the x axis
antoniya [11.8K]

First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

x(x-1)(x+2) = 0 \iff x=0\ \lor\ x-1=0\ \lor\ x+2=0

Which means that the roots are

x=0\ \lor\ x=1\ \lor\ x=-2

Next, we can expand the function definition:

y = x(x-1)(x+2) = x^3 + x^2 - 2x

In this form, it is much easier to compute the derivative:

y' = 3x^2+2x-2

If we evaluate the derivative in the points of interest, we have

y'(-2) = 6,\quad y'(0)=-2,\quad y'(1)=3

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

y-y_0=m(x-x_0)

is what we need. The three lines are:

y-0=6(x+2) \iff y = 6x+12  This is the tangent at x = -2

y-0=-2(x-0) \iff y = -2x  This is the tangent at x = 0

y-0=3(x-1) \iff y = 3x-3  This is the tangent at x = 1

7 0
3 years ago
7m+9, for m=2.<br> What's the value of this equation
Vinil7 [7]

Answer:

replace m with 2 and do 7(2)+9

5 0
3 years ago
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