0,0 if you’re looking for plot .
Since the velocity of the real plane is 0, p=mv=0. So the paper airplane actually has more momentum since it's value is not 0.
The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.
<h3>What is the mass of Jupitar?</h3>
There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.
Given that;
T^2 = GMr^3/4π
T = period
G = gravitational constant
r = radius
M = mass of Jupitar
Now;
1 day = 86400 seconds
1.77 days = 1.77 days * 86400 seconds/1 day
= 152928 seconds
Making M the subject of the formula;
M =4πT^2/Gr^3
M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3
M = 2.9 * 10^11/5.0 * 10^24
M = 5.8 * 10^-14 Kg
Learn more about mass of a planet:brainly.com/question/13851553
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<h2>Answer: It becomes an Ion
</h2>
When an atom has gained or lost electrons (negative charge), it becomes an ion.
In this sense:
<h2>I
ons are atoms that have <u>
gained or lost</u>
electrons in their electronic cortex.
</h2><h2>
</h2>
If a neutral atom <u>loses electrons</u>, it remains with an excess of positive charge and transforms into a positive ion or <u>cation</u>, whereas if a neutral atom <u>gains electrons</u>, it acquires an excess of negative charge and transforms into a negative ion or <u>anion</u>.
It is then how ions form bonds with other atoms differently depending on the number of electrons they have.
Answer:
a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)
b) The acceleration of point A is 3.25 m/s²
The acceleration of point E is 0.75 m/s²
Explanation:
a) The relative acceleration of B with respect to D is equal:
Where
aB = absolute acceleration of point B = 2.5 j (m/s²)
aD = absolute acceleration of point D = 1.5 j (m/s²)
(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam
(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)
We have that
(aB/D)t = BDα
Where α = acceleration of the beam
BDα = 1 m/s²
Where
BD = 2
b) The acceleration of point A is:
(aA/D)t = ADαj
The acceleration of point E is:
(aE/D)t = -EDαj
