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2 years ago

11

A cardboard box has four forces acting upon it, as shown in the diagram below. What is the magnitude of the unknown force, Funkn

ownacting on the box if the box is accelerating at 2.0 m/s 2 to the right?
(Answer choices)
A. 5N
B.6N
C.10 N
D. 11N

1 answer:

shutvik [7]2 years ago

4 0

D. 11N
Nznsnksksksksmsmsms

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A flat loop of wire consisting of a single turn ofcross-sectional area 7.90 cm2is perpendicular to a magnetic field that increas

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To develop this problem, it is necessary to apply the concepts related to Faraday's law and Magnetic Flow, which is defined as the change that the magnetic field has in a given area. In other words

$\Phi = BA Cos\theta$

Where

B= Magnetic Field

A = Area

$\theta =$ Angle between magnetic field lines and normal to the area

The differentiation of this value allows us to obtain in turn the induced emf or electromotive force.

In this case we have that the flat loop of wire is perpendicular to the magnetic field, therefore the angle is 0 degrees, since its magnetic field acts parallel to the area:

$\theta =$ 0 then our expression can be written as

$\Phi = BA$

From the same value of the electromotive force we have to

$\epsilon = -\frac{d\Phi}{dt}$

Replacing we have

$\epsilon = -A\frac{B}{dt}$

Replacing with our values we have that

$\epsilon = -(7.9*10^{-4}m)\frac{(3.5-0.5)}{0.1}$

$\epsilon = -0.0237V$

Therefore the magnitude of the induced emf in the loop is 0.0237V

On the other hand we have that the current by Ohm's Law can be defined as

$I = \frac{\epsilon}{R}$

For the given value of the resistance and the previously found potential we have to

$I = \frac{0.237}{1.3}$

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3 years ago

A positively charged object is placed to the left of a negatively charged object. Which best describes how the positively charge

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Explanation:

As per the law of electrostatics, two positive or negative charge repel each other while two opposite charge attract each other.
In this case, a positively charged object is placed to the left of a negatively charged object. It would mean that the positive charge move in the direction of negative charge, so as to attract each other.
Hence, the positively charged object will move to the right.

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3 years ago

A 1500 kg weather rocket accelerates upward at 10.0 m/s . It explodes 2.00 s after liftoff and breaks into two fragments, one tw

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20 m/s is the speed of the heavier fragment just after the explosion.

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = ma where, F = Force (Newton)

m= mass

a = acceleration

Given:

mass of rocket = M = 1500 kg

acceleration of rocket = a = 10 m/s²

elapsed time = t = 2.00 s

mass of lighter fragment = m₁ = m = 500 kg

mass of heavier fragment = m₂ = 2m = 1000 kg

maximum height of lighter fragment = h = 530 m

Let's calculate the final speed of the rocket just before the explosion:

v = u + at

v = 0 + 10(2)

v = 20 m/s

Then, we will calculate the height of the rocket just before the explosion:

$h' = ut + \frac{1}{2}at^{2}$

$h' = 0 + \frac{1}{2} (10)(2.00)^{2}$

$h' =20m$

The initial speed of lighter fragment just after the explosion:

$v^{2}$ ₁ $= u^{2}$ ₁ - $2g$ Δ $h$

$v^{2}$ ₁ $= u^{2}$ ₁ - $2g$ $(h - h')$

$0^{2} = u^{2}$ ₁ $- 2(9.8) (530-20)$

$u^{2}$ ₁ $=9996$

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Using Conservation of Momentum Law :

$M v=m$ ₁ $u$ ₁ $+ m$ ₂ $u$ ₂

$1500 (20)= 500(\sqrt{9996} ) + 1000u$ ₂

$u$ ₂ ≅ $- 20 m/s$

Learn more about Newton's law of motion here:

brainly.com/question/10454047

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