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puteri [66]
3 years ago
11

A cardboard box has four forces acting upon it, as shown in the diagram below. What is the magnitude of the unknown force, Funkn

ownacting on the box if the box is accelerating at 2.0 m/s 2 to the right?
(Answer choices)
A. 5N
B.6N
C.10 N
D. 11N
Physics
1 answer:
shutvik [7]3 years ago
4 0
D. 11N
Nznsnksksksksmsmsms
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The magnetic field inside a superconducting solenoid is 4.00 T. The solenoid has an inner diameter of 6.20 cm and a length of 26
Delvig [45]

Answer:

(a) The magnetic energy density in the field is 6.366 J/m³

(b) The energy stored in the magnetic field within the solenoid is 5 kJ

Explanation:

magnitude of magnetic field inside solenoid, B = 4 T

inner diameter of solenoid, d = 6.2 cm

inner radius of the solenoid, r = 3.1 cm = 0.031 m

length of solenoid, L = 26 cm = 0.26 m

(a) The magnetic energy density in the field is given by;

u _B = \frac{B^2}{2\mu_o} \\\\u _B = \frac{(4)^2}{2(4\pi*10^{-7})}\\\\u_B = 6.366*10^6 \ J/m^3

(b) The energy stored in the magnetic field within the solenoid

U_B = u_B V\\\\U_B = u_B AL

U_B = u_B(A)(L)\\\\U_B = 6.366*10^6(\pi * 0.031^2)(0.26) \\\\U_B = 4997.69 J\\\\U_B = 5 \ KJ\\

6 0
3 years ago
3 In a television tube, an electron starting from rest experiences a force of 4.0 × 10−15 N over a distance of 50 cm. The final
MAXImum [283]

Answer:

The final speed of the electron = 2.095×10⁸ m/s

Explanation:

From newton's fundamental equation of dynamics,

F = ma ........................Equation 1

Where F = force, m = mass of the electron, a = acceleration of the electron.

making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

Constant: m =  9.109×10⁻³¹ kg.

Substituting into equation 2

a = 4.0×10⁻¹⁵/9.109×10⁻³¹

a = 4.39×10¹⁶ m/s².

Using newton's equation of motion,

v² = u²+2as .......................... Equation 3

Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.

Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²

Substituting into equation 3

v² = 0² + 2(0.5)(4.39×10¹⁶)

v = √(4.39×10¹⁶)

v = 2.095×10⁸ m/s

Thus the final speed of the electron = 2.095×10⁸ m/s

7 0
3 years ago
true or false? short-wave heat radiation is given off by the earth when the earth absorbs long-wave radiation.
Greeley [361]

Answer:

Hope this helps u, pls mark me brainlist

Explanation:

The sun emits shortwave radiation because it is extremely hot and has a lot of energy to give off. Once in the Earth's atmosphere, clouds and the surface absorb the solar energy. The ground heats up and re-emits energy as longwave radiation in the form of infrared rays.

4 0
3 years ago
How can the motion of an object that is NOT moving change?​
Semenov [28]
Only if a force acts upon it, it can move.
6 0
3 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end just bef
stich3 [128]

Answer:

  v =  7.67 m/s  for L= 1m

Explanation:

Let's use the conservation of mechanical energy, at the highest point and the lowest point

Initial. Vertical ruler

       Em₀ = mg h

Final. Just before touching the floor

       Em_{f} = K = ½ I w²

      Em₀ = Em_{f}

      m g h = ½ I w²

The moment of inertia of a ruler that turns on one end is

      I = 1/3 m L²

Let's replace

      m g h = ½ (1/3 m L²) w²2

      g h = 1/6 L² w²

They ask for the speed of the end so the height h is equal to the length of the ruler

      g L = 1/6 L² w²

The linear and angular variables are related

      v = w r

     w = v / r

In this case the point of interest a in strangers r = L

     g L = 1/6 L² v² / L²

     v = √ 6 g L

Let's calculate

Assume that the length of the meter is L = 1 m

    v = √ (6 9.8 1)

   v =  7.67 m/s

7 0
3 years ago
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