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puteri [66]
3 years ago
11

A cardboard box has four forces acting upon it, as shown in the diagram below. What is the magnitude of the unknown force, Funkn

ownacting on the box if the box is accelerating at 2.0 m/s 2 to the right?
(Answer choices)
A. 5N
B.6N
C.10 N
D. 11N
Physics
1 answer:
shutvik [7]3 years ago
4 0
D. 11N
Nznsnksksksksmsmsms
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Ocean waves pass through two small openings, 20.0 m apart, in a breakwater. You're in a boat 70.0 m from the breakwater and init
Klio2033 [76]

Answer:

λ = 5.65m

Explanation:

The Path Difference Condition is given as:

δ=(m+\frac{1}{2})\frac{lamda}{n}  ;

where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.

m = no of openings which is 2

∴δ= \frac{3*lamda}{2}

n is the index of refraction of the medium in which the wave is traveling

To find δ we have;

δ= \sqrt{70^2+(33+\frac{20}{2})^2 }-\sqrt{70^2+(33-\frac{20}{2})^2 }

δ= \sqrt{4900+(\frac{66+20}{2})^2}-\sqrt{4900+(\frac{66-20}{2})^2}

δ= \sqrt{4900+(\frac{86}{2})^2 }-\sqrt{4900+(\frac{46}{2})^2 }

δ= \sqrt{4900+43^2}-\sqrt{4900+23^2}

δ= \sqrt{4900+1849}-\sqrt{4900+529}

δ= \sqrt{6749}-\sqrt{5429}

δ=  82.15 -73.68

δ= 8.47

Again remember; to calculate the wavelength of the ocean waves; we have:

δ= \frac{3*lamda}{2}

δ= 8.47

8.47 = \frac{3*lamda}{2}

λ = \frac{8.47*2}{3}

λ = 5.65m

3 0
4 years ago
Which tool would be most useful to identify areas with frequent earthquakes to predict future earthquakes?
enyata [817]
It is a seismograph that would be most useful.
6 0
3 years ago
A 100kg cannon at rest contains a 10kgcannonball. when fired,
slega [8]

Answer:

9 m/s

Explanation:

mass of cannon, M = 100 kg

mass of cannon ball, m = 10 kg

velocity of cannon ball, v = 90 m/s

Let the recoil velocity of cannon is V.

Us ethe conservation of linear momentum, as no external force is acting on the system, so the linear momentum of the system is conserved.

Momentum before the firing = momentum after the firing

M x 0 + m x 0 = M x V + m x v

0 = 100 x V + 10 x 90

V = - 9 m/s

Thus, the recoil velocity of cannon is 9 m/s.

4 0
3 years ago
A circular conducting loop with a radius of 0.10 m and a small gap filled with a 10.0 ȍresistor is oriented in the xy-plane. If
lidiya [134]

Answer:

The magnitude of the current is 5.45 mA.

Explanation:

Given that,

Resistance = 10.0 ohm

Radius = 0.10 m

Magnetic field = 1.0 T

Angle = 30°

Increase magnetic field = 7.0 T

Time t = 3.0 s

Number of turns = 1

We need to calculate the initial flux

Using formula of flux

\phi=NB_{1}A\cos\theta

Put the value into the formula

\phi=1\times1.0\times\pi\times(0.10)^2\times\cos30^{\circ}

\phi=1\times1.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}

\phi=0.027\ wb

We need to calculate the final flux

\phi=1\times7.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}

\phi=0.1904\ wb

We need to calculate the induced emf

Using formula of emf

\epsilon=\dfrac{\phi_{f}-\phi_{i}}{t}

Put the value into the formula

\epsilon=\dfrac{0.1904-0.027}{3.0}

\epsilon=0.0545\ V

We need to calculate the current

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value into the formula

I=\dfrac{0.0545}{10.0}

I=5.45\ mA

Hence, The magnitude of the current is 5.45 mA.

4 0
3 years ago
A child pulls a wagon at a constant velocity of 4.0 m/s for 4.0 minutes along a level sidewalk. The child does this applying a 2
natita [175]

Answer:

288kj

Explanation:

3 0
3 years ago
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