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krek1111 [17]
3 years ago
13

A commercial oven with a book value of $67,000 has an estimated remaining 5 year life. A proposal is offered to sell the oven fo

r $8,500 and replace it with a new oven costing $110,000. The new machine has a 5-year life with no residual value. The new machine would reduce annual maintenance costs by $23,000. REQUIRED Provide a differential analysis on the proposal to replace the commercial oven.
Chemistry
1 answer:
baherus [9]3 years ago
8 0

Answer:

$13,500

Explanation:

The differential analysis of the proposal to replace the commercial oven is shown below:-  

The Total differential decrease in cost = Annual maintenance cost reduction × Number of years applicable

= $23,000 × 5

= $115,000  

Inflow cash = The Total differential decrease in cost + Proceeds from sale of equipment

= 115,000 + $8,500

= $123,500

The Net differential decrease in cost from replacing equipment = Inflow cash - Cost of new equipment

= $123,500 - $110,000

= $13,500

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ratelena [41]

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The frequency of wave is 0.125 Hz.

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5 0
3 years ago
An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the
Misha Larkins [42]

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

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3 0
3 years ago
46.6 grams of mercury II sulfate (HgSO4) reacts with an excess of sodium Chloride (NaCl). How many grams of mercury II chloride
slega [8]

Answer:

m_{HgCl_2}=42.7gHgCl_2

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2

Best regards.

3 0
2 years ago
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