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krek1111 [17]
3 years ago
13

A commercial oven with a book value of $67,000 has an estimated remaining 5 year life. A proposal is offered to sell the oven fo

r $8,500 and replace it with a new oven costing $110,000. The new machine has a 5-year life with no residual value. The new machine would reduce annual maintenance costs by $23,000. REQUIRED Provide a differential analysis on the proposal to replace the commercial oven.
Chemistry
1 answer:
baherus [9]3 years ago
8 0

Answer:

$13,500

Explanation:

The differential analysis of the proposal to replace the commercial oven is shown below:-  

The Total differential decrease in cost = Annual maintenance cost reduction × Number of years applicable

= $23,000 × 5

= $115,000  

Inflow cash = The Total differential decrease in cost + Proceeds from sale of equipment

= 115,000 + $8,500

= $123,500

The Net differential decrease in cost from replacing equipment = Inflow cash - Cost of new equipment

= $123,500 - $110,000

= $13,500

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luda_lava [24]
Gasoline use contributes to air pollution
Gasoline is a toxic and highly flammable liquid. The vapors given off when gasoline evaporates and the substances produced when gasoline is burned (carbon monoxide, nitrogen oxides, particulate matter, and unburned hydrocarbons) contribute to air pollution. Burning gasoline also produces carbon dioxide, a greenhouse gas.
5 0
3 years ago
A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of magnesium fluoride in
mojhsa [17]

The question is incomplete, here is the complete question:

A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of chemist's working solution is 5.90\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock magnesium fluoride solution

M_2\text{ and }V_2 are the molarity and volume of chemist's magnesium fluoride solution

We are given:

M_1=0.00154M\\V_1=230mL\\M_2=?M\\V_2=600mL

Putting values in above equation, we get:

0.00154\times 230=M_2\times 600\\\\M_2=\frac{0.00154\times 230}{600}=5.90\times 10^{-4}M

Hence, the concentration of chemist's working solution is 5.90\times 10^{-4}M

8 0
3 years ago
How many moles are in 11.2 L of helium gas?
puteri [66]

Answer:

16 is the answer

Explanation:

0.5 x 32 = 16

8 0
3 years ago
Read 2 more answers
Find the values of n, l, m, and s for the 9th electron
Oduvanchick [21]

Answer:

The values of all four quantum number for 9th electron are:

n = 2

l = 1

m = 3

s = + 1/2

Explanation:

There are four quantum numbers:

Principal quantum number (n)

Azimuthal quantum number (l)

Magnetic quantum number (ml)

Spin quantum number (ms)

All these four quantum numbers gives complete information about an electron like its spin, shells, subshells and orbitals.

For example:

The all four quantum values for 9th electron are:

It is the last electron of fluorine;

F₉ = 1s², 2s², 2p⁵

The last 9th electron is in second orbital the principle quantum number will be 2.

Azimuthal quantum number (l)

The azimuthal quantum number describe the shape of orbitals. its value foe s, p, d, f... are 0, 1, 2, 3. For 9th electron its value will be (n-1) 1.

Magnetic quantum number (ml)

It describe the orientation of orbitals. Its values are -l to +l. For l=1  the ml will be -1 ,0,+1.

Spin quantum number (ms)

The spin quantum  number tells the spin of electron either its clock wise (+1/2) or anti clock wise (-1/2).

For last electron of fluorine spin quantum number will be

+1/2 because it occupy full empty 2Pz. If 10th electron will added then its spin will be -1/2.

6 0
4 years ago
A. 207 kJ<br> B. 4730 kJ<br> C. 9460 kJ<br> D. 414 kJ
MrMuchimi

Answer:

Q = 9460 Kj

Explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram copper is 4730 Kj thus, for 2 kg

by putting values,

Q= 2kg ×  4730 Kj/Kg

Q = 9460 Kj

6 0
3 years ago
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