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Ronch [10]
3 years ago
14

An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the

molar mass (g/mol) of Q
Chemistry
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

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7 0
3 years ago
There are 50 fish in the pond that have tags. You catch 25 fish, and 5 of them have tags. What is the best estimate of the numbe
sergeinik [125]

Answer: 250


Explanation:


You work this problem by using proportions.


A proportion is the equalization of two ratios.


Here you assume that the ratio of fish with tags to total fish that you catch is the same than the ratio of fish with tags to total fish in the pond.


Mathematically:

  • 5 fish with tag / 25 fish = 50 fish with tag / x
  • 5 / 25 = 50 / x

Solve for x:

  • Multiplication property of equality: x × 5 = 50 × 25
  • Division property of equality: x = 50 × 25 / 5
  • Result: 250
8 0
2 years ago
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Consider this reaction:
ryzh [129]

Answer:

I think it's 6 moles are produced

3 0
2 years ago
the daily dose of ampicillin for the treatment of an ear infection is 115 mg/kg of body weight. what is the daily dose for a 43-
Lorico [155]
M=43lb = 19,5kg

If 115mg --------- is for --------- 1kg
                             so
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x = 19,5kg * 115mg / 1kg
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Since you have given (C3H8)=11 g
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(
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(
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m
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n
(
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In this question it is quite hard to explain the use of significant figures. Those are used to imply a certain inaccuracy. Not enough information is given by the question, as of how accurate the measurement is. It is a mere exercise of converting one property into another. Here you should not worry about it.
5 0
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