The tension that is contained in this cord when the block is at its lowest is 39.24N
<h3>How to solve for the tension</h3>
Given data
mass = M = 2 kg
unstretched length= 0.5 m
mass of the cord 5 g = 0.005 kg
spring constant = k = 100 N/m
We have to compare with potential energy we have = Mgh = Mgx
g = acceleration due to gravity = 9.81
comparing with kinetic energy we have = 1/2 ke^2 = 1/2 kx^2
equating both energies
1/2 kx^2 = Mgx
dividing both sides by x gives
1/2 kx = Mg
evaluating further gives
kx = 2Mg = Tension in the cord
therefore tension in the cord = 2Mg
= 2 * 2 * 9.81
tension T = 39.24N
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Answer:
the amount of orbital angular momentum that an electron has in respect to a particular axis of rotation.
Explanation:
The energy of a single photon is given by:
where
E is the energy
h is the Planck constant
f is the frequency of the light
The light in our problem has a frequency
, so the energy of each photon of that light is:
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