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2 years ago

Just a question anybody playing minècraft here?

Physics

2 answers:

yan [13]2 years ago

5 0

Answer:

yes/nope

Explanation:

............... :)

Liula [17]2 years ago

5 0

Yup!

Brainliest would be nice!

Have a great day!!

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Two adjacent natural frequencies of an organ pipe are found to be 550. Hz and 650. Hz. (a) Calculate the fundamental fre- quency

liubo4ka [24]

Answer:

a) 100Hz

b) opened at both ends

c) 1.72m

Explanation:

Let fun be the nth Harmonic frequency organ. If pipe is opened at both ends.

L= length of pipe

Fyn =(n/x)

550hz= (n/2L)v 1

650hz=(n+1/2L)×v 2

Comparing 1 and 2

650hz= nv/2L + v/2L

550= 343/2L

L= 550×2/343 = 1.7m

c) fundamental frequency

Fo= nv/2L = 343/(2×1.7) = 100Hz

8 0

3 years ago

You are driving along the New York State Thruway in a line of cars all travelling at a constant speed of 108.5 km/hr. The car in

IgorC [24]

Answer:

Car first should be 30.13 m behind the second car.

Explanation:

Given that,

Constant speed = 108.5 Km/hr

Time = 1 sec

Let the distance covered by second car S and by first car S'

We need to calculate the distance covered by second car

Using equation of motion

$S=ut-\dfrac{1}{2}at^2$ .....(I)

The distance covered by first car to avoid collision

$S''=S'+S$

Put the value into the formula

$S'+S=ut+ut-\dfrac{1}{2}at^2$ ...(II)

We need to calculate the distance covered by first car

Using equation (I) and (II)

$S'=ut$

Put the value into the formula

$S'=108.5\times\dfrac{5}{18}\times1$

$S'=30.13\ m$

Hence, Car first should be 30.13 m behind the second car.

7 0

3 years ago

An explosion in a rigid pipe shoots three balls out of its ends. A 6 gam ball comes out the right end. A 4 gram ball comes out t

wariber [46]

Answer:

The third ball emerges from the right side.

Explanation:

This is a conservation of Momentum problem

In an explosion or collision, the momentum is always conserved.

Momentum before explosion = Momentum after explosion

Since the rigid pipe was initially at rest,

Momentum before explosion = 0 kgm/s

- Taking the right end as the positive direction for the velocity of the balls

- And calling the speed of the 6 g ball after explosion v

- This means the velocity of the 4 g ball has to be -2v

- Mass of the third ball = m

- Let the velocuty of the third ball be V

Momentum after collision = (6)(v) + (4)(-2v) + (m)(V)

Momentum before explosion = Momentum after explosion

0 = (6)(v) + (4)(-2v) + (m)(V)

6v - 8v + mV = 0

mV - 2v = 0

mV = 2v

V = (2/m) v

Note that since we have established that the sign on m and v at both positive, the sign of the velocity of the third ball is also positive.

Hence, the velocity of the third ball according to our convention is to the right.

Hope this Helps!!!

5 0

4 years ago

Read 2 more answers

On which planet would you weigh less?

shtirl [24]

Answer:

i think f witch is mars

Explanation:

....

7 0

3 years ago

Read 2 more answers

Can you please help me figure out the work for the missing quantities?

marysya [2.9K]

Answer: set up proportions

Explanation:

8 0

3 years ago