The value of mass m = 0.506kg
Initial frequency = 0.78Hz
additional mass = 730 g = 0.73kg
New frequency = 0.65 Hz
F = 1/2π 
0.78 = 1/2π 
additional mass,
0.65 = 1/2π 
1.44 = k/m / k/m+0.73
1.44 = m+0.73 / m
1.44m -m = 0.73
1.44m = 0.73
mass m = 0.506kg
a measurement used in physics to express the inertia, a quality that all matter has in common. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilograms is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one kilogramme times one square metre per second. The kilogramme is determined by precise measurements of Planck's constant, while the second and metre are already defined in terms of other physical constants.
Learn more about mass here:
brainly.com/question/506625
#SPJ4
Answer:
52.5 J
Explanation:
Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.
i.e W = F × s
It is a scalar quantity and measured in Joules (J).
Given that: F = 35.0 N and s = 1.50 m, then;
W = F × s
W = 35.0 × 1.5
= 52.5 J
Therefore, the work done on the sleigh by Samuel is 52.5 J.
Answer:
0.28m/s²
Explanation:
Force = mass•acceleration
F = m•a
50 = 176•a Divide both sides by 176:
50/176 = a ≈ 0.28 m/s²
Answer:
C. the net force on the object
Explanation:
That is because Force= mass x acceleration. The question says that we know the mass and acceleration, which means that it would be the force that resulted in the acceleration of the mass.
Answer:
The magnitude of the frictional force is 48.02 N
Explanation:
Mass of box = 20 kg
Weight of the box (Normal reaction) = mass × acceleration due to gravity = 20 ×9.8 = 196 N
Horizontal force applied = 48 N
Coefficient of friction = horizontal force ÷ normal reaction = 48 ÷ 196 = 0.245
Frictional force = coefficient of friction × normal reaction = 0.245 × 196 N = 48.02 N
