Answer:
Δ v = 125 m/s
Explanation:
given,
mass of space craft = 435 Kg
thrust = 0.09 N
time = 1 week
= 7 x 24 x 60 x 60 s
change in speed of craft = ?
Assuming no external force is exerted on the space craft
now,
a = 2.068 x 10⁻⁴ m/s²
using equation of motion
Δ v = a t
Δ v = 2.068 x 10⁻⁴ x 7 x 24 x 60 x 60
Δ v = 125 m/s
Car A experienced a greater impulse, because it stopped in a shorter amount of time.
Impulse is defined as the change in force over time. Since both cars have the same mass, as well as the same initial and final velocities, the only factor that makes a difference is the time taken to achieve the stop.
Answer:
<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong):</em>
a) a×b = 34.27k
b) a·b = 128.43
c) (a + b)·b = 305.17
d) The component of a along the direction of b = 9.66
Explanation:
<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong)</em> we can proceed as follows:
a) The vectorial product, a×b is:
b) The escalar product a·b is:
c) <u>Asumming (a</u><u> </u><u>+ b)·b</u> <em>instead a+b·b</em> we have:
d) The component of a along the direction of b is:
I hope it helps you!
Answer:
1010713.18851 Pa
387999.259089 N
Explanation:
= Atmospheric pressure =
r = Radius = 2 m
h = Depth = 10 m
= Density of liquid methane =
g = Acceleration due to gravity = 7.44 m/s²
A = Area
Force is given by
The force exerted is 1010713.18851 Pa
The weight of the column of methane is 387999.259089 N
The pressure at a depth is given by
The pressure at the depth is