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marysya [2.9K]
3 years ago
13

According to the second law of thermodynamics, it is impossible for ____________. According to the second law of thermodynamics,

it is impossible for ____________. heat energy to flow from a colder body to a hotter body an ideal heat engine to have the efficiency of 99% an ideal heat engine to have non-zero power. a physical process to yield more energy than what is put in
Physics
1 answer:
Tomtit [17]3 years ago
7 0

Answer:

It's impossible for an ideal heat engine to have non-zero power.

Explanation:

Option A is incomplete and so it's possible.

Option B is possible

Option D is related to the first lae and has nothing to do with the second law.

Hence, the correct option is C.

The ideal engine follows a reversible cycle albeit an infinitely slow one. If the work is being done at this infinitely slow rate, the power of such an engine is zero.

We can also stat the second law of thermodynamics in this manner;

It is impossible to construct a cyclical heat engine whose sole effect is the continuous transfer of heat energy from a colder object to a hotter one.

This statement is known as second form or Clausius statement of the second law.

Thus, it is possible to construct a machine in which a heat flow from a colder to a hotter object is accompanied by another process, such as work input.

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Suppose that the hatch on the side of a Mars lander is built and tested on Earth so that the internal pressure just balances the
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Answer:

The value is  F_{net} =  4444 lb

The force will be  outward

Explanation:

From the question we are told that

   The diameter of the disk is  d = 50.0 \ cm  = \frac{50}{100} = 0.5 \ m

   The external pressure on Mars  is P = 650 \ N/m^2

From the question we are told that  

   Internal pressure  =  External pressure

Generally the external Force on earth is

      F_E = P_{atm} * A

Here P_{atm} is the atmospheric pressure with value  P_{atm} = 1.013*10^{5}\ Pa

So

      F_E = 1.013 *10^{5} * \pi * \frac{d^2}{4}

=>   F_E = 1.013 *10^{5} *3.142 * \frac{0.50 ^2}{4}

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Generally the external Force on Mars is  

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      F = 650 * \pi * \frac{d^2}{4}

=>   F = 650 *3.142 * \frac{0.5^2}{4}

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Net force is mathematically represented as

      F_{net} = F_E -F

=>    F_{net} =  19893  -127.6

=>    F_{net} =  19765.6 \ Nconverting to  pounds

    F_{net} = \frac{19765.6}{4.448}

=> F_{net} =  4444 lb

Given that that the value is positive then the force will be  outward

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Answer:

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