1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
3 years ago
14

What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?

Physics
1 answer:
makkiz [27]3 years ago
7 0

Answer:1.7\times 10

Explanation:

Given

Force F=7 N

time interval t=2.5 s

Impulse is given by =Force \times time\ interval\ for\ applied\ force

Impulse=7\times 2.5=17.5

For two significant Figure

Impulse=1.7\times 10

                       

You might be interested in
A person runs with a constant velocity of 1.2 m/s for 30 seconds. how far do they travel?
Nataliya [291]
They will travel 36 m
8 0
3 years ago
The photo shows a skateboarder pushing her foot against the ground as she rides down a hill.
Alinara [238K]

Answer:

yes

Explanation:

please Mark my answer in brainlist and follow me

4 0
2 years ago
Electrical wire with a diameter of .5 cm is wound on a spool with a radius of 30 cm and a height of 24 cm.
kow [346]

Answer:

a)   # lap = 301.59 rad , b)   L = 90.48 m

Explanation:

a) Let's use a direct proportions rule (rule of three). If one turn of the wire covers 0.05 cm, how many turns do you need to cover 24 cm

          # turns = 1 turn (24 cm / 0.5 cm)

         # laps = 48 laps

Let's reduce to radians

        # laps = 48 laps (2 round / 1 round)

       # lap = 301.59 rad

b) Each lap gives a length equal to the length of the circle

          L₀ = 2π R

          L = # turns L₀

          L = # turns 2π R

          L = 48 2π 30

          L = 9047.79 cm

          L = 90.48 m

6 0
3 years ago
A spaceship is traveling toward Earth while giving off a constant radio signal with a wavelength of 1 meter (m). What will the s
Nadya [2.5K]

Answer:

Less than 1 m

Explanation:

When objects are getting closer to each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the blue shift of waves. Here, the wavelength reduces.

In the opposite case the when objects are getting farther from each other there is a slight change in the wavelength that is being transmitted by either objects. This is known as the red shift. Here, the wavelength increases.

In this case the spaceship is getting close to Earth hence the wavelength will be lower than 1 m.

4 0
3 years ago
The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m
BARSIC [14]

A) The resultant force is 30.4 N at 25.3^{\circ}

B) The resultant force is 18.7 N at 43.9^{\circ}

Explanation:

A)

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

F_1 = 20 N at 0^{\circ} above x-axis

F_2 = 15 N at 60^{\circ} above y-axis

Resolving each force:

F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N

F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N

So, the components of the resultant are:

F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N

And the magnitude of the resultant is:

F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}

B)

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

\theta=180^{\circ}-60^{\circ}=120^{\circ}

So we have:

F_{2x}=F_2 cos \theta = (15)(cos 120)=-7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 120)=13.0 N

So, the components of the resultant this time are:

F_x = F_{1x}+F_{2x}=20-7.5 = 12.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N

And the magnitude is:

F=\sqrt{F_x^2+F_y^2}=\sqrt{13.5^2+13.0^2}=18.7 N

And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0
3 years ago
Other questions:
  • Find an equation for the plane that passes through the point [1, 1, 8] and that has [-1, -6, 3] as normal vector.
    15·1 answer
  • Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied
    15·1 answer
  • The observation location A is located at < 0.112, 0.247, 0 > m. The conventional current running through the wire is 7.5 a
    15·1 answer
  • If the earth was a spinning globe , what would happen to the oceans?
    8·1 answer
  • A car on a Ferris wheel has an angular displacement of π 4 rad, which corresponds to an arc length of 28.2 m. What is the Ferris
    11·1 answer
  • If you added 5 x more mass into a wheelbarrow, how much greater would
    9·1 answer
  • If 1.0 joule of work is required to move a charge of 1.0 coulomb between two points is an electric field the potential differenc
    13·1 answer
  • A wind turbine has a total input power of 2 500 kW.
    6·1 answer
  • Consider a stone and a football both at rest and having the same mass. why is it painful to kick the stone than to kick the foot
    8·1 answer
  • What does cardiorespiratory fitness measure?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!