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2 years ago

What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?

Physics

1 answer:

makkiz [27]2 years ago

7 0

Answer: $1.7\times 10$

Explanation:

Given

Force $F=7 N$

time interval $t=2.5 s$

Impulse is given by $=Force \times time\ interval\ for\ applied\ force$

$Impulse=7\times 2.5=17.5$

For two significant Figure

$Impulse=1.7\times 10$

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3 years ago

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fgiga [73]

Answer:

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3 years ago

A circuit is set up such that it has a current of 8 A. What would be the new current if the resistance was increased by a factor

RUDIKE [14]

Answer:

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The equation can also be rewritten as

$I=\frac{V}{R}$

from which we see that the current is inversely proportional to the resistance, R.

In this problem, the initial current is I = 8 A. Then the resistance is doubled:

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3 years ago

After driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average

belka [17]

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$X = \frac{F_s}{x} \\X = \frac{1909.4}{k}$

I assume a value of $K=4*10^4N/m$

$X= \frac{1909.4}{4*10^4} = 0.48m$

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3 years ago

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Lena [83]

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2 years ago

Read 2 more answers