3 years ago

What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?

Physics

1 answer:

makkiz [27]3 years ago

7 0

Answer: $1.7\times 10$

Explanation:

Given

Force $F=7 N$

time interval $t=2.5 s$

Impulse is given by $=Force \times time\ interval\ for\ applied\ force$

$Impulse=7\times 2.5=17.5$

For two significant Figure

$Impulse=1.7\times 10$

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