Answer:
Dimension of the enclosure is 56.56 ft * 14.14 ft
Step-by-step explanation:
Given -
Let us suppose that x is the length of steel fence and y is the length of one side of pine boards
We know that - xy = 800.
y = 800/x
Let us say that C is the cost of fence
= 3x + 6(2y) = 3x + 12y = 3x + 12(800/x)
C = 3x + 9600x-1, x > 0
C' = 3 - 9600x-2 = (3x2-9600)/x2
C' = 0 when 3x2 = 9600
x2 = 3200
x = √3200 ft ≈ 56.56 ft
So, the cost is minimized when x ≈ 56.56 ft and y = 800/x ≈ 14.14 ft
2(x + 7) - 1 > 15 3(x + 2) < 2x + 7
2x + 14 - 1 > 15 3x + 6 < 2x + 7
2x + 13 > 15 3x - 2x < 7 - 6
2x > 15 - 13 x < 1
2x > 2
x > 2/2
x > 1
so, x > 1 OR x < 1.....all real numbers except 1
The greatest common factor of 32x^-2y^2 is 2 (there is o common variable and both 32 and 2 divide by 2)
Thus, divide each term by 2
32x^2/2 = 16x^2
-2y^2 = -1y^2 = -y^2
Thus, your answer is
2(16x^2-y^2)
I'll help but what are u supposed to do
Wouldn't the answer be: 435.84m
