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DedPeter [7]
3 years ago
9

Is frying something a physical or chemical change?

Chemistry
2 answers:
photoshop1234 [79]3 years ago
7 0
Frying something is a Chemical change.
Take frying an egg for example. The egg white turns solid and this chemical reaction can't be reversed. This is because the egg white is made of proteins and due to the heat the enzymes get denatured meaning it can't do its function properly anymore.
Yakvenalex [24]3 years ago
6 0

i believe it is chemical change.

hope it helps

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Is light and sound matter? why or why not?
Kipish [7]
Light and sound aren't matter because Photons have no mass.
3 0
2 years ago
Can you answer all of the questions plz
NARA [144]
No..............................
3 0
3 years ago
Read 2 more answers
Based on the following reaction, determine how much heat is released if 500. grams of methane is combusted in excess oxygen: CH4
EastWind [94]

Answer:

- 13,150.6kJ

Explanation:

CH4 + 2 O2 ------> CO2 + 2 H2O ΔH= – 890 kJ

The ΔH is enthalpy change of combustion , which is the heat is either absorbed or released by the combustion of one mole of a substance.

ΔH=−890 kJ/mol (released in the combustion of one mole of methane)

using the molar mass  (in grams )of methane to get moles of sample

(237g × 1 mole of CH4)/16.04g=14.776 moles  of CH4

Since 1 mole produces 890 kJ of heat upon combustion, then 14.776 moles will produce

ΔH = 14.776moles of CH4 × 890kJ/1mole of CH4

=13,150.6kJ

Therefore ΔH = - 13,150.6kJ

3 0
3 years ago
A sample can not be broken down physically or chemically what is it
KIM [24]

Answer:

Pure Substance. A sample of matter, either a single element or a single compound, that has definite chemical and physical properties. Element. A pure substance that cannot be broken down into other substances by chemical or physical means.

Explanation:

Sorry if it's wrong!!!!!!!

6 0
3 years ago
Read 2 more answers
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
2 years ago
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