Answer:
408.33g
Explanation:
The equation for the reaction is given below :
2KClO3 → 2KCl + 3O2
We'll begin by obtaining the mass of the KClO3 and O2 from the balanced equation. This can be achieved as shown below:
Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 39 + 35.5 + 48 = 122.5g/mol
Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96g
From the equation, 245g of KClO3 produced 96g of O2.
Therefore, Xg of KClO3 will produce 160g of O2 i.e
Xg of KClO3 = (245 x 160)/96 = 408.33g
Therefore, 408.33g of KClO3 are needed.
