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denpristay [2]
3 years ago
5

Given that a x 60 = b what is the value of 4b/a

Mathematics
2 answers:
Marysya12 [62]3 years ago
5 0

Answer:

The value of  \frac{4b}{a}   is   240

Step-by-step explanation:

We were given the equation: a x 60 = b

To find the value of 4b/a, we are going to follow the following step;

First, divide both-side of the equation by a, thus our equation becomes:

 a x 60/a   =  b/a

On the left-hand side of the equation, 'a' at the numerator will cancel-out 'a' at the denominator. Our equation becomes;

60 = b/a

Then, the next step is to multiply 4 to both-side of the equation, our equation becomes

4 x 60 = 4 x b/a

240 = \frac{4b}{a}

\frac{4b}{a}  =240

Therefore, the value of  \frac{4b}{a} is 240

Ainat [17]3 years ago
3 0

Answer:

240

Step-by-step explanation:

Given

60a = b ( divide both sides by a )

60 = \frac{b}{a} ( multiply both sides by 4 )

240 = \frac{4b}{a}

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4 0
2 years ago
Carlos is 33 years younger than Kristen. 2 years ago, Kristen's age was 2 times Carlos's age. How old is Carlos now?
ale4655 [162]

Answer:

Carlos is 35 years old now

Step-by-step explanation:

Assume that Carlos is x years old now

∵ Carlos is x years old now

∵ Carlos is 33 years younger than Kristen

- Kirsten's age is the sum of x and 33

∴ Kirsten is x + 33 years old now

2 years ago

∵ Carlos's age = x - 2

∵ Kristen's age = x + 33 - 2 = x + 31

∵ Kristen's age was 2 times Carlos's age

- Equate Kristen's age by 2 times Carlos's age

∴ x + 31 = 2(x - 2)

- Simplify the right hand side

∴ x + 31 = 2x - 4

- Subtract x from both sides

∴ 31 = x - 4

- Add 4 to both sides

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6 0
3 years ago
Purchasing A regional survey found that 70% of all families who indicated an intention to buy a new car bought a new car within
zheka24 [161]

Answer:

If a family chosen at random bought a car, we need to find the probability that the family had not previously indicated an intention to buy a car = P(I'|B) = 0.3362

Step-by-step explanation:

Let the event that a family that intends to buy a car be I

Let the event that a family does not intend to buy a car be I'

Let the event that a family buys a car in those 3 months be B

Let the event that a family does not buy a car in those 3 months be B'

Given,

P(B|I) = 0.70

P(B|I') = 0.10

P(I) = 0.22

P(I') = 1 - P(I) = 1 - 0.22 = 0.78

If a family chosen at random bought a car, we need to find the probability that the family had not previously indicated an intention to buy a car = P(I'|B)

The conditional probability P(A|B), is given as

P(A|B) = P(A n B) ÷ P(B)

So,

P(B|I) = P(B n I) ÷ P(I)

P(B n I) = P(B|I) × P(I) = 0.70 × 0.22 = 0.154

P(B|I') = P(B n I') ÷ P(I')

P(B n I') = P(B|I') × P(I') = 0.10 × 0.78 = 0.078

P(B) = P(B n I) + P(B n I') = 0.154 + 0.078 = 0.232

P(B') = 1 - 0.232 = 0.768

P(I'|B) = P(B n I') ÷ P(B)

= 0.078 ÷ 0.232 = 0.3362

Hope this Helps!!!

8 0
3 years ago
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