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2 years ago

Given that a x 60 = b what is the value of 4b/a

Mathematics

2 answers:

Marysya12 [62]2 years ago

5 0

Answer:

The value of $\frac{4b}{a}$ is 240

Step-by-step explanation:

We were given the equation: a x 60 = b

To find the value of 4b/a, we are going to follow the following step;

First, divide both-side of the equation by a, thus our equation becomes:

a x 60/a = b/a

On the left-hand side of the equation, 'a' at the numerator will cancel-out 'a' at the denominator. Our equation becomes;

60 = b/a

Then, the next step is to multiply 4 to both-side of the equation, our equation becomes

4 x 60 = 4 x b/a

240 = $\frac{4b}{a}$

$\frac{4b}{a}$ =240

Therefore, the value of $\frac{4b}{a}$ is 240

Ainat [17]2 years ago

3 0

Answer:

240

Step-by-step explanation:

Given

60a = b ( divide both sides by a )

60 = $\frac{b}{a}$ ( multiply both sides by 4 )

240 = $\frac{4b}{a}$

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2 years ago

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bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

2 years ago