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Daniel [21]
3 years ago
12

A sock drawer contains 18 blue socks and 10 black socks. If two socks are randomly drawn from the drawer without replacement, wh

at is the probability that two black socks are chosen? (in simplest fraction form)
Mathematics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer:

what do you mean?

Step-by-step explanation:


harina [27]3 years ago
4 0
I wanna say 1/14 but I'm really not sure
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A survey report states that 70% of adult women visit their doctors for a physical examination at least once in two years. If 20
irakobra [83]

Answer:

a) 0.3921 = 39.21% probability that fewer than 14 of them have had a physical examination in the past two years.

b) 0.107 = 10.7% probability that at least 17 of them have had a physical examination in the past two years.

Step-by-step explanation:

For each women, there are only two possible outcomes. Either they visit their doctors for a physical examination at least once in two years, or they do not. The probability of a woman visiting their doctor at least once in this period is independent of any other women. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of adult women visit their doctors for a physical examination at least once in two years.

This means that p = 0.7

20 adult women

This means that n = 20

(a) Fewer than 14 of them have had a physical examination in the past two years.

This is:

P(X < 14) = 1 - P(X \geq 14)

In which

P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 14) = C_{20,14}.(0.7)^{14}.(0.3)^{6} = 0.1916

P(X = 15) = C_{20,15}.(0.7)^{15}.(0.3)^{5} = 0.1789

P(X = 16) = C_{20,16}.(0.7)^{16}.(0.3)^{4} = 0.1304

P(X = 17) = C_{20,14}.(0.7)^{17}.(0.3)^{3} = 0.0716

P(X = 18) = C_{20,18}.(0.7)^{18}.(0.3)^{2} = 0.0278

P(X = 19) = C_{20,19}.(0.7)^{19}.(0.3)^{1} = 0.0068

P(X = 20) = C_{20,20}.(0.7)^{20}.(0.3)^{0} = 0.0008

So

P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1916 + 0.1789 + 0.1304 + 0.0716 + 0.0278 + 0.0068 + 0.0008 = 0.6079

P(X < 14) = 1 - P(X \geq 14) = 1 - 0.6079 = 0.3921

0.3921 = 39.21% probability that fewer than 14 of them have had a physical examination in the past two years.

(b) At least 17 of them have had a physical examination in the past two years

P(X \geq 17) = P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

From the values found in item (a).

P(X \geq 17) = P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0716 + 0.0278 + 0.0068 + 0.0008 = 0.107

0.107 = 10.7% probability that at least 17 of them have had a physical examination in the past two years.

6 0
2 years ago
If x is a positive integer then the solution set of 4x+2&lt;14 is
taurus [48]
4x + 2 < 14
4x < 14 - 2
4x < 12
x < 12/4
x < 3 S = { x <3 }
3 0
3 years ago
What is the dimension of a rectangle if the perimeter is 198
AfilCa [17]

Answer:

Length = 49.5 unit and width = 49.5 unit

Step-by-step explanation:

Given as , Perimeter of rectangle = 198 unit

so ,as Perimeter of rectangle = 2× ( Length + width)

Or,                                   198 = 2 ×  (Length + width)

Or,                                   \frac{198}{2} = length + width

So, length + width = 99 unit

Now to make area maximum

Length × width = maximum

Or, (99 - width ) × width = maximum

      99 Width - width² = maximum                              Let width = W

Now differentiate both side with respect to W

D(99W - W²)\frac{D(99w - w^2)}{Dw} = 0         as, constant diff is 0

So, 99 - 2w = 0

Or, w = \frac{99}{2}

Or, w = 49.5 unit    and L = 99- 4905 = 49.5 unit      Answer

3 0
3 years ago
How many possible combinations of 6 numbers?
enot [183]
 9*8*7*6*5*4 = 60480. Hope this helps !!!!!!!!!!!!!!!!!!!1
8 0
3 years ago
Help me pls ! if you do l give you the brainiest
Zina [86]
The first answer is correct because the terms are alike in both expressions
5 0
3 years ago
Read 2 more answers
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