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Verdich [7]
3 years ago
6

What are the reactants for Stage 2 of photosynthesis, and where do they come from? (15 points if answer)

Chemistry
2 answers:
devlian [24]3 years ago
8 0

Answer:

In photosynthesis, chlorophyll, water, and carbon dioxide are reactants. GA3P and oxygen are products. In photosynthesis, water, carbon dioxide, ATP, and NADPH are reactants.

Explanation:

Mariulka [41]3 years ago
3 0

Answer:  In photosynthesis, chlorophyll, water, and carbon dioxide are reactants. GA3P and oxygen are products. In photosynthesis, water, carbon dioxide, ATP, and NADPH are reactants.

Explanation: i don't really know  how i did it

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True................
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Which describes the products created from fission reactions? Question 3 options:
Ipatiy [6.2K]

<u>Answer:</u> The correct answer is option A.

<u>Explanation:</u>

Nuclear fission reactions are a type of nuclear reactions in which larger nuclei breaks apart into two or more smaller fragment releasing alpha, gamma of beta particles.

There are 3 types of particles that can be released during this process:

1. Alpha particles: These particles are released when a nuclei undergoes alpha-decay process.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

2. Beta particles: These particles are released when a nuclei undergoes beta-minus decay process.

_Z^A\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^0\beta

3. Gamma radiations: these radiations are released when an unstable nuclei gives off excess energy by a process of spontaneous electromagnetic process.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

Hence, any of these particles can be released during the process of fission reaction with smaller atoms.

Therefore, the correct answer is option A.

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3 years ago
Aluminum can react with oxygen gas to produce aluminum oxide (Al2O3). What type of reaction is this?
Pachacha [2.7K]

It's Synthesis, single replacement is incorrect.

6 0
4 years ago
How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and
Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)

The expression used will be:  

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = heat released for the reaction = ?

m = mass of benzene = 94.4 g

c_{p,s} = specific heat of solid benzene = 1.51J/g^oC=1.51J/g.K

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

\Delta H_{fusion} = enthalpy change for fusion = -9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g

Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

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3 years ago
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10.0gNaCl/2.0Lsolution= 5.0g/L
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