<span>Let x = the miles Jeanie ran
y = the miles Jeanie biked
T = 2 hours total time for the duathlon
v1 = 8.5 mph Jeanie's running speed and
v2 = 16 mph Jeanie's biking speed
But T = Jean's time she ran t1 + time she biked t2 I. e t1 + t2 = 2
So we have average speed v2 when she biked = distance (y) / time (t2)
Distance y = v2 * t2 = 16 * t2 and distance when she ran x = 8.5 * t1
Since she covered 27 miles while running and biking we have
x + y = 27
8.5t1 + 16t2 =27 ------(1)
t1 + t2 = 2 --------------(2)
The simultaneous equation gives us
t1 = 2/3 and t2 which is time she biked = 4/3
So 4/3 = 1 1/3. Which is 1 hour 20 minutes</span>
This is a problem pertaining projectile motion wherein the parameter we're finding is the angle of inclination denoted as theta. The formula to be used is the range:
Range = v^2*sin(2*theta)*(1/g)
100 = (60^2) * sin(2*theta) * (1/32.2)
theta=31.7°
I hope I was able to help you. Have a good day!
So basically your gonna regaurd 63.5 as 60 +3.5, 60 is 5*12 and the remaining 3.5 is less than the divisor 5, so it would be the remainder
anwser is 63.5/5 treat as 60/5+3.5/5
so anwser is 60/5+3.5/5=0.7=12.7
Answer:
x=-6, y=0
Step-by-step explanation:
Use the 3x-9y=-18 equation and add 9y to both sides to have 3x on its own on the left side. Then, divide by 3 on both sides. Then you'll have x=-6+3y. Plus this back into the 5x+4y=-30 equation and you'll get 5(-6+3y)+4y=-30. Use the distributive property and you'll get -30+15y+4y=-30. Simplify and get -30+19y=-30, then add 30 to both sides and you'll get 19y=0. Divide by 19 on both sides and you'll get y=0. Now that we know y=0, plug that back into the 5x+4y=-30 equation, and you'll get 5x+4(0)=-30. Simplify and you'll get 5x=-30. Divide by 5 on both sides and you'll get x=-6.
