Question

I think these two are simple questions.. but I need help asap..... TT

Answer 1

1) The average velocity is 56 m/min

2) The average velocity is -83 m/min

Explanation:

1)

The average velocity of an object is given by

$v=\frac{d}{t}$

where

d is the displacement (change in position)

t is the time elapsed

In the graph in the problem, the displacement corresponds to the distance, therefore to the change in the y-variable ($\Delta y$), while the time elapsed is the change in the x-variable ($\Delta x$), so the average velocity can be written as

$v=\frac{\Delta y}{\Delta x}$

At point A, we have:

$y_A = 5 m\\x_A = 0.1 min$

At point B, we have:

$y_E = 55 m\\x_A = 1 min$

So, we have

$\Delta y= 55 -5 = 50 m\\\Delta x = 1.0-0.1 = 0.9 min$

So the average velocity is

$v=\frac{50 m}{0.9 min}=56 m/min$

2)

In this part instead, we have the following:

At point F, we have:

$y_F = 55 m\\x_A = 1.3 min$

At point H, we have:

$y_H = 30 m\\x_A = 1.6 min$

So, we have

$\Delta y= 30 -55 = -25 m\\\Delta x = 1.6-1.3 = 0.3 min$

So the average velocity is

$v=\frac{-25 m}{0.3 min}=-83 m/min$

Learn more about velocity:

brainly.com/question/8893949

brainly.com/question/5063905

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