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Akimi4 [234]
3 years ago
10

4n+9 = -3 I need help to solve this problem

Mathematics
1 answer:
vekshin13 years ago
6 0
N= -3 and here is why, 4 times -3 equals -12. If you add 9 to -12 you get -3. 
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Afina-wow [57]

Answer:

Aww thats cute

Step-by-step explanation:

5 0
3 years ago
Which equation represents grants path? <br>A. y=2-4x<br>B. y=4-x/2<br>C. y=6-x/4<br>D. y=8-2x​
EleoNora [17]

Answer:

C.

Step-by-step explanation:

recall that the point-slope form of a linear equation is given by

y = mx + c

Rearranging so that it is in the same form as the answer choices, we get

y = c + mx

where m is the slope and c is the y-intercept

we note the following observations

1) The line goes from top left to bottom right, this means that the slope is negative, hence m has to be negative. (in our case, all the choices have negative x)

2) The line crosses the y-axis at y = 4, this means the y-intercept is 4 and hence c = 4.

If we look at the choices, only choice B satisfies both observations (that m is negative and c = 4)

6 0
3 years ago
Read 2 more answers
Can someone explain this
horsena [70]

9514 1404 393

Answer:

  • resultant force: 93.946∠-10.62° N
  • line of action: 17.314x +92.337y = 809.433

Step-by-step explanation:

We can use the notation a∠b to represent the (x, y) components (a·cos(b), a·sin(b)), where angle b is measured CCW from the +x direction. If we label the forces a, b, c, d clockwise from A, then we have ...

  a = 80∠0° = (80, 0)

  b = 60∠90° = (0, 60)

  c = 90∠45° = (63.640, 63.640)

  d = 150∠-110° = (-51.303, -140.954)

__

If we label point A the origin, then the clockwise torque on point A is the sum of products of the force x-component and its y location, and its y-component and the negative of its x location.

  T = (0, 0)·(80, 0) +(3, 0)·(0, 60) +(3, -8)·(63.640, 63.640) +(0, -8)·(-51.303, -140.954)

  T = 809.433 . . . . n·m, the CW torque on point A

__

The sum of forces is ...

  F = a +b +c +d = (92.337, -17.314) = 93.946∠-10.62° . . . N

__

This force, applied to the point of application, must generate the same torque as the given forces. That is ...

  F·(y, -x) = 809.433

Then the equation of the line of action is ...

  17.314x +92.337y = 809.433 . . . . . x and y in meters measured from A

Any point (x, y) on this line will serve as a point of application of the force. Unfortunately, this line of action does not pass through the rectangular plate. The attachment shows the point (D) on the line of action that is closest to point A.

_____

<em>Additional comment</em>

The resultant force could be decomposed into two forces acting <em>on the rectangular plate</em>. One could be of much larger magnitude, operating at the corner opposite point A. This force would provide the necessary torque. Another would be acting on point A, providing no torque, but with components such that the resultant has the correct magnitude and direction.

6 0
3 years ago
When 6x^2-4x+3 is subtracted from 3x^2-2x+3 The result is
Svetach [21]
3x^2 -6x + 6 :) hope this is alright
4 0
3 years ago
Read 2 more answers
Write 289% in decimal form.
Veseljchak [2.6K]
There r 2 ways to do this....percent to decimal

(1) u can divide by 100.....289/100 = 2.89
(2) u can move the decimal 2 spaces to the left....2.89

just so u know ... decimal to percent
(1) multiply by 100
(2) move decimal 2 spaces to right
3 0
3 years ago
Read 2 more answers
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