The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.
<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2
p = -2, h=0, k=0</span><span>
focal width = |4*(-2)| = 8
The answer to your question is that the length of the focal width is equal to 8.</span>
We're looking for a solution of the form
. By the chain rule, this solution should have total differential

and the equation is exact if the mixed second-order partial derivatives of
are equal, i.e.
.
The given ODE is exact, since


Then




With
, we get


Answer:
Multiply the second equation's terms by 3. Solve for x.
Step-by-step explanation:
You will get:
2x+9y=28
9x-9y=42
Add them to get:
11x=70.
You can solve from there.
Answer:
3 3/8
Step-by-step explanation: