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Nostrana [21]
4 years ago
12

The perimeter of a square in which A=36in2

Mathematics
1 answer:
cupoosta [38]4 years ago
6 0

Answer:

24 inches

Step-by-step explanation:

The area of the square is 36 in2. The area of square can be represented as side x side or side squared. So, the sides must be 6 inches in length since 6x6 is 36. If one side is 6, 4 sides are 24.

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<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0</span><span>

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.</span>
3 0
3 years ago
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Show that (2xy3 + cos x)dx + (3x2 y2 − sin y)dy = 0 is exact, and find the solution. Find c if y(0) = π
Licemer1 [7]

We're looking for a solution of the form F(x,y)=C. By the chain rule, this solution should have total differential

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Answer:

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