Question

A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the arm of the centrifuge is 21m what is the speed of the centrifuge?

Answer 1

Answer:

$approx.= 25\frac{m}{s}$

Explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

$a=\frac{V^{2} }{r}$

which allows us to solve for the velocity:

$V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...$