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2 years ago

How do protons, neutrons and electrons determine the properties of the atoms??? HELP! NEED SCIENCE HELP FAST!!!!

1 answer:

4 0

The number of protons determines the element. Many elements also have many isotopes. Such as carbon-14 Carbon-12 and carbon-10.

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1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?

Mila [183]

Answer:

press dat crown for meh

Explanation:

4 0

2 years ago

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You pull with a force of 77 N on a piece of luggage of mass 23 kg, but it does

Vinvika [58]

Answer:

The force of static friction acting on the luggage is, Fₓ = 180.32 N

Explanation:

Given data,

The mass of the luggage, m = 23 kg

You pulled the luggage with a force of, F = 77 N

The coefficient of static friction of luggage and floor, μₓ = 0.8

The formula for static frictional force is,

Fₓ = μₓ · η

Where,

η - normal force acting on the luggage 'mg'

Substituting the values in the above equation,

Fₓ = 0.8 x 23 x 9.8

= 180.32 N

Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N

5 0

3 years ago

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A Person whose weight is 5.20 x 10^2 N is being pulledup

Gnoma [55]

Answer:

Explanation:

Given

Weight of Person $W=5.20\times 10^{2} N$

Cave is $h=35.1 m$ deep

Breaking stress $T=569 N$

Net Force on Person

$F_{net}=569-520=49 N$

$a_{net}=\frac{F_{net}}{\frac{W}{g}}$

$a_{net}=\frac{49}{\frac{520}{9.8}}$

$a_{net}=0.923 m/s^2$

The shortest time such that the person can be taken out of cave

$h=ut+\frac{1}{2}at^2$

where

h=distance moved

t=time

a=acceleration

$35.1=0+\frac{1}{2}(0.923)(t)^2$

$t^2=76.05$

$t=\sqrt{76.05}$

$t=8.72\ s$

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2 years ago

Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth

zimovet [89]

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

Work done = force x distance

Weight is a force in the presence of gravity;

Work done = weight x height of lifting

Height of lifting = $\frac{work done }{weight}$

Height of lifting = $\frac{250}{50}$ = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

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2 years ago

Graphs help you see ______.

Anastaziya [24]

D- if i was right please mark me as a brainliest answer and a thank you

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2 years ago

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