3 years ago

How do protons, neutrons and electrons determine the properties of the atoms??? HELP! NEED SCIENCE HELP FAST!!!!

1 answer:

4 0

The number of protons determines the element. Many elements also have many isotopes. Such as carbon-14 Carbon-12 and carbon-10.

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Describe what has happened when a player "fumbles" the ball. (American Football)

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Answer:

The players drops the ball either do to contact, the ball being stripped or personal error

Explanation:

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3 years ago

A radio wave has a frequency of 8.6 × 108 hz. what is the energy of one photon of this radiation (h = 6.63 × 10–34 j • s)?

My name is Ann [436]

Answer: $57.018\times10^{-26}J$

Energy is directly proportional to the frequency.

The energy of a photon is given by:

$E=h\nu$

Where, E is the energy and $\nu$ is the frequency.

Frequency of the radio wave is given:

$\nu=8.6\times10^8 Hz$

$h=6.63\times10^{-34}J.s$

Multiply the above two:

Energy,

$E=h\nu=6.63\times10^{-34}J.s\times8.6\times10^8 Hz= 57.018\times10^{-26}J$

Hence, the energy of each photon of radio wave having frequency $\nu=8.6\times10^8 Hz$ is $57.018\times10^{-26}J$

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3 years ago

Two students 8 meters apart are holding a stretched, coiled spring between them. One student sends a pulse down the string, and

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Answer:

Explanation:

Distance travelled by wave = 8 x 2 = 16 m

Time taken = 4 s

velocity of pulse wave = distance / time

= 16 m / 4 s

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3 years ago

A particle that is moving along a straight line accelerates from 40 cm/s to 20 cm/s in 5.0 s and then has a constant acceleratio

Marrrta [24]

Answer:

Average speed, $v_{avg}=43.33\ \rm cm/s$

Explanation:

Given:

Initial speed, u=40 cm/s
final speed , v=20 cm/s
Time taken, t=5 s

<u>First case</u>

Using equation of motion we have

$2as=v^2-u^2\\2as=20^2-40^2\\as=-600\\$

Now using,

$v=u +at\\20=40+a\times5\\a=-4\ \rm cm/s^2$

now putting the value of a in first equation we get

$s=150\ \rm cm$

<u>Second case</u>

Acceleration $a=20\ \rm cm/s^2$

Time taken $t=4\ \rm s$

using equation of motion in one Dimension we have

$s=ut+\dfrac{at^2}{2}\\\\s=20\ties 4+\dfrac{20\times 4^2}{2}\\s=240\ \rm cm$

Average speed is equal to total distance travelled per unit total time taken

$v_{avg}=\dfrac{150+240}{5+4}\\v_{avg}=43.33\ \rm cm/s$

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4 years ago

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B) All nonzero digits are significant.

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3 years ago

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