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Alborosie
3 years ago
5

The angular speed of the hour hand of a clock, in rad/min, is:___________

Physics
1 answer:
lapo4ka [179]3 years ago
4 0

The angular speed is defined as:

<h2>                                      ω=\frac{2\pi}{T}</h2>

        where

                                     T=12*60=720min

                                     \omega=\frac{2\pi}{720}

                                     \omega=4.4**10^{-3} rad/min

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_____ can alter wind flow and create a rain shadow effect. Beaches Lakes Mountains Oceans
Ket [755]
The correct answer is Mountains. Mountains can alter wind flow and create a rain shadow effect. A mountain is a large landform and is high surrounding a limited area. It is generally steeper and higher than a hill.
5 0
3 years ago
Read 2 more answers
Grains of fine california beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide,
kykrilka [37]

The average radius(r) of each grain is r = 50 nanometers = 50*10^-6 meters

Since it is spherical, so

 Volume=(4/3)*pi*r^3

V= (4/3)*pi*(50*10^-6)^3

V=5.23599*10^-13 m^3

 

We are given the Density(ρ) =2600kg/m^3

 

We know that:

Density(p) = mass(m)/volume(V)

m = ρV

 

So the mass of a single grain is:

m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg

 

 

The surface area of a grain is:

a = 4*pi*r^2

a = 4*pi*(50*10^-6)^2

a = 3.14*10^-8 m^2

 

 

Since we know the surface area and mass of a grain, the conversion factor is:

1.361357*10^-9 kg / 3.14*10^-8 m^2

 

Find the Surface area of the cube:

cube = 6a^2

cube = 6*1.1^2  = 7.26m^2

 

multiply this by the converions ratio to get:

total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg) / (3.14*10^-8 m^2)

total mass of sand grains = 0.3148 kg = 314.80 g

3 0
3 years ago
How long must a flute be in order to have a fundamental frequency of 262 Hz (this frequency corresponds to middle C on the evenl
spin [16.1K]

Answer:

L=0.654 m

Explanation:

<u>Concepts and Principles  </u>

1- The speed of sound in air is expressed as a function of the temperature of air as follows:  

 v=(331 m/s)√(1+T_C/273°C)                        (1)

where 331 m/s is the speed of sound in air at temperature 0°C and Tc is the temperature of air in Celsius.  

<u>Standing Wave Patterns in Pipes:  </u>

A pipe open at both ends can have standing wave patterns with resonant frequencies:  

f=v/λ=nv/2L                     n=1,2,3.........

where v is the speed of sound in air.  

<u>Given Data </u>

f_1 (fundamental frequency of the flute) = 262 Hz

T (temperature of the air) = 20°C  

The flute is open at both ends.  

<u>Required Data </u>

We are asked to determine the length of the tube.  

<u>Solution</u><u>  </u>

The speed of sound in air at temperature T = 20°C is found from Equation (1):

 v=(331 m/s)√(1+T_C/273°C)  

 =342.91 m/s

The fundamental frequency of the flute is found by substituting n = 1 into Equation (2):  

f=v/2L

Solve for L:  

L=v/2f_1

L=0.654 m

7 0
2 years ago
Which of these best describes heat transfer through conduction? A) Heat transfer as electrons are excited in atoms. B) Heat tran
Setler79 [48]
I'd go for D here. It also fits in with the idea of thermal expansion - as something is heated up, molecules vibrate and maybe collide. they vibrate with bigger amplitudes, so taking up more space, so expanding. maybe
7 0
3 years ago
Read 2 more answers
If a 10. m3 volume of air (acting as an ideal gas) is at a pressure of 760 mm and a temperature of 27 degrees Celsius is taken t
kow [346]
We know, the ideal gas equation, 
P1V1 / T1 = P2V2 / T2

Here, P1 = 760 mm
V1 = 10 m3
T1 = 27 + 273 = 300 K

P2 = 400 mm Hg
T2 = -23 + 273 = 250 K

Substitute their values, 
760*10 / 300 = 400 * V2 / 250
25.33 * 250 = 400 * V2
V2 = 6333.333/ 400
V2 = 15.83

In short, Your Answer would be approx. 15.83 m3

Hope this helps!
7 0
3 years ago
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