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2 years ago

An outside thermometer reads 57°F. What is this temperature in °C? Round your answer to the nearest whole number.

Physics

2 answers:

marishachu [46]2 years ago

3 0

Answer: It'd be 14.

Explanation:

The formula for this equation would be (57f-32)×5/9 which is equal to 13.889; and rounding that to the whole number would be 14.

Fiesta28 [93]2 years ago

3 0

Answer-

a) 14

Explanation:

Fahrenheit to Celsius Formula: (°F - 32) / 1.8 = °C

= [57-32]/1.8=C

=25/1.8=C

=13.8888888889

round off 13.8888888889=14

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Suppose a man pushes a crate with a force of 20 N north. What is the magnitude and direction of the reaction force?

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2 years ago

a wave is described by where x is in meters, y is in centimeters and t is in seconds. The angular frequency is

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Complete Question

A wave is described by y(x,t) = 0.1 sin(3x + 10t), where x is in meters, y is in centimetres and t is in seconds. The angular wave frequency is

Answer:

The value is $w = 10 \ rad /s$

Explanation:

From the question we are told that

The equation describing the wave is y(x,t) = 0.1 sin(3x + 10t)

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$y(x,t) = Asin(kx + wt )$

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Now comparing this equation with that given we see that

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3 years ago

How do sports play a role in American Culture? Is this different from how sports play a role in other cultures?

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2 years ago

Suppose that you have been chosen for a space mission to a distant planet. Due to the length of time you'll be away from Earth y

Contact [7]

Answer:

I should be active for 15 hours to meet the physical activity requirement.

Explanation:

Since time dilates in moving objects, we use the formula t = t₀/√(1 - β²) where t = time in space vehicle, t₀ = time on earth = 9 hours and β = v/c where v = speed of space vehicle = 0.8c.

So, t = t₀/√(1 - β²)

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= 9/√(1 - (0.8c/c)²)

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8 0

3 years ago

"A steel rotating-beam test specimen has an ultimate strength of 120 kpsi. Estimate the life of the specimen if it is tested at

MrRissso [65]

Answer:

life (N) of the specimen is 117000 cycles

Explanation:

given data

ultimate strength Su = 120 kpsi

stress amplitude σa = 70 kpsi

solution

we first calculate the endurance limit of specimen Se i.e

Se = 0.5× Su .............1

Se = 0.5 × 120

Se = 60 kpsi

and we know strength of friction f = 0.82

and we take endurance limit Se is = 60 kpsi

so here coefficient value (a) will be

a = $\frac{(f\times Su)^2}{Se}$ ......................1

put here value and we get

a = $\frac{(0.82\times 120)^2}{60}$

a = 161.4 kpsi

so coefficient value (b) will be

b = $-\frac{1}{3}log\frac{(f\times Su)}{Se}$

b = $-\frac{1}{3}log\frac{(0.82\times 120)}{60}$

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so here number of cycle N will be

N = $(\frac{ \sigma a}{a})^{1/b}$

put here value and we get

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N = 117000

so life (N) of the specimen is 117000 cycles

7 0

3 years ago