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erastovalidia [21]
3 years ago
11

Cindy pours cool milk into a hot bowl of oatmeal and then stirs it with a room-temperature spoon. Which substance will have heat

flow from it to the other substances? the milk
the spoon
the oatmeal
the surrounding air
Physics
2 answers:
djverab [1.8K]3 years ago
6 0
Answer:
The oatmeal

Explanation:
It’s the oatmeal that had the most thermal energy out of the four options. The milk was cool, the spoon was at room temperature and the surrounding air was also at room temperature, leaving the heat from the oatmeal will travel to those substances.

I hope this helps!
Pavlova-9 [17]3 years ago
6 0
The answer is “the oatmeal”
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Is it possible for a system to have negative potentialenergy?
sineoko [7]

Answer:

Yes, since the choice of the zero o potential energy is arbitrary.

Explanation:

The kinetic energy is due to the motion of the object. The expression for the kinetic energy is as follows;

KE=\frac{1}{2}mv^{2}

Here, m is the mass of the object and v is the velocity of the object.

The kinetic energy can not be negative as the velocity is squared. It can be zero and positive.

Potential energy: It is the energy is due to the position of the object.

The expression for the potential energy is as follows;

PE= mgh

Here, g is the acceleration due to gravity and height.

Height can be taken from the reference point, zero which can be taken below zero and above zero. Zero is taken as origin. Below zero, the height is taken as negative and above zero, the height is taken as positive.

The potential energy can be zero, positive and negative.

The total energy is the sum of kinetic energy and potential energy.

E= KE + PE

Here, KE is the kinetic energy and PE is the potential energy.

Therefore, the option (B) is correct.

5 0
3 years ago
What is the value of work done on an object when a 70 newton force moves it 9.0 meters in the same direction as the force
olchik [2.2K]
<span>Work, very simply, equals force times distance (when the force and distance are in the same direction. otherwise you get a little bit of trig added on) \[W=F*\Delta x\] W=70N * 9.0 m = 630 Nm = 630 J</span>
3 0
3 years ago
Read 2 more answers
The weight of a body kept at a distance of 6400 km from the centre of the
Vlad [161]

Answer:

2.5N

Explanation:

since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1

so the weight will be reduced to 1/4 of 10N

6 0
3 years ago
A solid aluminum sphere of radius R has moment of inertia I about an axis through its center. What is the moment of inertia abou
frutty [35]

Answer:

I1 = 2/5 M1 R^2   for a sphere about its center

I2 = 2/5 M2 (2 R)^2 = 2/5 M2 R^ * 4 = 8/5 M2 R^2

Remember that M2 is greater than M1 by a factor 0f 2^3 = 8

Then I2 exceeds I1 by a factor of 32

6 0
3 years ago
Does the horizontal distance d travelled by the ball depend on the height of release? If it does depend on the height, what is t
elena-s [515]

Answer:

Explanation:

Yes , the horizontal distance travelled by the ball will depend upon the height of release .

When a ball is thrown at some angle from a height , it has two components , the vertical component and horizontal component . The ball goes in horizontal direction due to its horizontal component . Its vertical component has no role to play .  But the horizontal range covered by the body thrown

depends upon the duration of time in which it remains in air . The longer it remains in air , the greater distance it can cover horizontally .

Horizontal distance covered = t x horizontal velocity

If V be the velocity of throw and Vx be its horizontal component

Horizontal distance covered = t x Vx

Now t depends upon the height . If height rises , time of fall will increase so horizontal distance covered will increase .

If h be the height from which the body is thrown , Vy be the vertical upward component of initial velocity

from the relation

s = ut + 1/2 at²

h = - Vy t  + 1/2 at²

As h increases , t will increase and therefore horizontal distance covered will increase. If the ball has only  horizontal velocity initially , Vy = 0

h = 1/2 gt²

t = \sqrt{\frac{2h}{g} }

Horizontal distance covered  = t x Vx

= \sqrt{\frac{2h}{g} } \times  V_x

From this expression also

Horizontal distance covered is proportional to \sqrt{h} .

7 0
3 years ago
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