Match the statement to symbols<br> a quarter of a number<br> 4/x<br> 4x<br> ox/4<br> 1/4+x

A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0

2 years ago

Please help me. look at the picture.

Butoxors [25]

It’s 0.775x +2.5 =correct

6 0

2 years ago

The lengths of nails produced in a factory are normally distributed with a mean of 3.34 centimeters and a standard deviation of

Shtirlitz [24]

Answer:

3.47 and 3.21

Step-by-step explanation:

Let us assume the nails length be X

$X \sim N(3.34,0.07^2)$

Value let separated the top 3% is T and for bottom it would be B

$P(X < T)= 0.97$

Now converting, we get

$P(Z < \frac{T-3.34}{0.07})= 0.97$

Based on the normal standard tables, we get

$P(Z < 1.881)= 0.97$

Now compare these two above equations

$\frac{T-3.34}{0.07} = 1.881 \\\\ T = 1.881 \times 0.07 + 3.34 \\\\ = 3.47$

So for top 3% it is 3.47

Now for bottom we applied the same method as shown above

$P(Z < \frac{B-3.34}{0.07})= 0.03$

Based on the normal standard tables, we get

$P(Z < -1.881)= 0.03$

Now compare these two above equations

$\frac{B-3.34}{0.07} = -1.881$

$= -1.881 \times 0.07 + 3.34 \\\\ = 3.21$

hence, for bottom it would be 3.21

7 0

3 years ago

I need help for this question plz

ExtremeBDS [4]

Y=180-69=111
4x+7=y
4x+7=111
4x=111-7
4x=104
X=26

Answer: x=26, y=111

4 0

3 years ago

PLEASE ANSWER QUICKLY

Olegator [25]

Answer:

x=3

Step-by-step explanation:

Set equations equal to each other:

$x^3-3x^2+2=x^2-6x+11$

Subtract two from both sides

$x^3-3x^2=x^2-6x+9$
Factor out x^2 from the left side

$x^2(x-3)=x^2-6x+9$

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

$x^2(x-3) = (x-3)(x-3)$

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.

this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0

It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.

So one of the real solutions is at x=3

6 0

2 years ago

Match the statement to symbols a quarter of a number 4/x 4x ox/4 1/4+x