Question

Balance the given molecular equations in aqueous solution with coefficients and phases for each species. If you determine that a species should have a coefficient of 1, you must indicate this with the "1" label. Do not leave the coefficient space blank for any species in the balanced equation.
1 2 3 4 5 6 s aq

K2SO4 ( )+ Pb(NO3)2 ( ) → KNO3 ( )+ PbSO4 ( )
Ca(C2H3O2)2 ( )+ (NH4)2CO3 ( ) → CaCO3()+ NH4C2H3O2()
Li3PO4( )+ BaCl2 ( ) → LiCl ( ) + Ba3(PO4)2 ( )
MgBr2( ) + NaOH ( ) → Mg(OH)2 ( ) + NaBr ( )

Answer 1

Answer:

- $1K_2SO_4 (aq)+ 1Pb(NO_3)_2 (aq) \rightarrow 2KNO_3 (aq)+ 1PbSO_4 (s)$

- $1Ca(C_2H_3O_2)_2 (aq)+ 1(NH_4)_2CO_3 (aq) \rightarrow 1CaCO_3(s)+ 2NH_4C_2H_3O_2(aq)$

- $2Li_3PO_4(aq)+3 BaCl_2 (aq) \rightarrow 6LiCl (aq) + Ba_3(PO_4)_2 (s)$

- $1MgBr_2(aq) + 2NaOH (aq) \rightarrow 1Mg(OH)_2 (s) + 2NaBr (aq)$

Explanation:

Hello,

In this case, we must make equal the number of atoms of each element at both reactants and products as shown below:

(a) Lead (II) sulfate precipitates out.

$K_2SO_4 (aq)+ Pb(NO_3)_2 (aq) \rightarrow KNO_3 (aq)+ PbSO_4 (s)\\\\1K_2SO_4 (aq)+ 1Pb(NO_3)_2 (aq) \rightarrow 2KNO_3 (aq)+ 1PbSO_4 (s)$

(b) Calcium carbonate precipitates out.

$Ca(C_2H_3O_2)_2 (aq)+ (NH_4)_2CO_3 (aq) \rightarrow CaCO_3(s)+ NH_4C_2H_3O_2(aq)\\\\1Ca(C_2H_3O_2)_2 (aq)+ 1(NH_4)_2CO_3 (aq) \rightarrow 1CaCO_3(s)+ 2NH_4C_2H_3O_2(aq)$

(c) Barium phosphate precipitates out.

$Li_3PO_4(aq)+ BaCl_2 (aq) \rightarrow LiCl (aq) + Ba_3(PO_4)_2 (s)\\\\2Li_3PO_4(aq)+3 BaCl_2 (aq) \rightarrow 6LiCl (aq) +1Ba_3(PO_4)_2 (s)$

(d) Magnesium hydroxide precipitates out.

$MgBr_2(aq) + NaOH (aq) \rightarrow Mg(OH)_2 (s) + NaBr (aq)\\\\1MgBr_2(aq) + 2NaOH (aq) \rightarrow 1Mg(OH)_2 (s) + 2NaBr (aq)$

Best regards.