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Brut [27]
3 years ago
7

A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) H

ow much time is required to reach this height?
Physics
1 answer:
valina [46]3 years ago
5 0

Answer:

Question A:17.92 m/s

Question B:0.6 seconds

Explanation:

Question A:

Initial velocity(u)=24m/s

Height(h)=13m

acceleration due to gravity(g)=9.8m/s^2

Final velocity=v

v^2=u^2-2xgxh

v^2=24^2-2x9.8x13

v^2=24x24-2x9.8x13

v^2=576-254.8

v^2=321.2

Take them square root of both sides

v=√(321.2)

v=17.92m/s

Question B:

velocity(v)=17.92m/s

Acceleration due to gravity(g)=9.8m/s^2

Initial velocity(u)=24m/s

Time=t

v=u-gxt

17.92=24-9.8xt

Collect like terms

9.8t=24-17.92

9.8t=6.08

Divide both sides by 9.8

9.8t/9.8=6.08/9.8

t=0.6 approximately

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Answer:Magnitude of tension in the string is less than the weight of rock

Explanation:

Given

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3 0
4 years ago
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Fed [463]

To explain how transverse and longitudinal waves work, let us give two examples for each particular case.

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8 0
4 years ago
Usually the force of gravity on electrons is neglected. To see why, we can compare the force of the Earth’s gravity on an electr
miv72 [106K]

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Explanation:

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Substituting,

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By comparison, the gravitational force exerted on the electron is:

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kakasveta [241]

Answer:

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Solnce55 [7]

Answer:

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