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sasho [114]
4 years ago
13

What is the difference between transverse and longitudinal waves?

Physics
1 answer:
Fed [463]4 years ago
8 0

To explain how transverse and longitudinal waves work, let us give two examples for each particular case.

In the case of transverse waves, the displacement of the medium is PERPENDICULAR to the direction of the wave. One way to visualize this effect is when you have a rope and between two people the rope is shaken horizontally. The shift is done from top to bottom. This phenomenon is common to see it in solids but rarely in liquids and gases. A common application usually occurs in electromagnetic radiation.

On the other hand in the longitudinal waves the displacement of the medium is PARALLEL to the direction of propagation of the wave. A clear example of this phenomenon is when a Slinky is pushed along a table where each of the rings will also move. From practice, sound waves enclose the definition of longitudinal wave displacement.

Therefore the correct answer is:

C. In transverse waves the displacement is perpendicular to the direction of propagation of the wave, while in longitudinal waves the displacement is parallel to the direction of propagation.

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Sunny_sXe [5.5K]

That part of the wave is called a compression.

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4 years ago
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No official standard exists for extinguisher-cylinder colors. that said, a red cylinder is typically associated with which type
Lorico [155]
Fire extinguishers are typically red. Goes along with the red fire trucks and red being a color of emergency. While there isn't any standard, if we decided to change the colors of the fire extinguisher, people would be very confused and given the context, it could cost people's lives, so I'm thinking red will be the color of fire extinguishers for a while to come.
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4 years ago
A composite load consists of three loads connected in parallel. One draws 100 W at a PF of 0.92 lagging, another takes 250 W at
fenix001 [56]

Answer:

a) I_{RMS} = 4.79 A

b) PF = 0.908

Explanation:

Get the reactive powers for each of the loads:

Reactive power = Real Power * tanθ

For load 1

Active power, P₁ = 100 W

Power factor, cos \theta_{1} = 0.92

\theta_{1} = cos^{-1} 0.92\\\theta_{1} = 23.074

Q_{1}= P_{1} tan \theta_{1} \\Q_{1}= 100tan 23.074\\Q_{1}= 42.60 W

For load 2

Active power, P₂ = 250 W

Power factor, cos \theta_{2} = 0.8

\theta_{2} = cos^{-1} 0.8\\\theta_{2} = 36.87

Q_{2}= P_{1} tan \theta_{2} \\Q_{2}= 250tan 36.87\\Q_{2}= 187.5 W

For load 3

Active power, P₃ = 250 W

Power factor, cos \theta_{3} = 1

\theta_{3} = cos^{-1} 1\\\theta_{3} =0

Q_{2}= P_{1} tan \theta_{3} \\Q_{3}= 150tan 0\\Q_{3}= 0 W

Calculate the total reactive power, Q_{net} = 42.6 + 187.5 + 0

Q_{net} = 230.1 W

Calculate the total active power, P_{net} = 100 + 250 + 150 = 500 W

S_{net} = P_{net} + Q_{net} \\S_{net} = 500 + j230.1

P_{net} = IVcos \theta_{net}

\theta_{net} = tan^{-1} \frac{230.1}{500} \\\theta_{net} = 24.712

V = 115 V_{rms}

500 = I_{RMS}  * 115 cos 24.712\\I_{RMS} = 500/104.47\\ I_{RMS} = 4.79 A

b) Power factor of the composite load is cos\theta_{net}

\theta_{net}  = 24.712\\PF = cos 24.712\\PF = 0.908

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OLEGan [10]

Answer:C

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A=0.05.0M.

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