Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The expression is 
Explanation:
Generally smallest workdone done by a gas is mathematically represented as
Generally for an isothermal process
=> 
Generally the total workdone is mathematically represented as
=> 
=> ![nRT [lnV] | \left \ {V_f}} \atop {V_o}} \right.](https://tex.z-dn.net/?f=nRT%20%5BlnV%5D%20%20%20%7C%20%5Cleft%20%5C%20%7BV_f%7D%7D%20%5Catop%20%7BV_o%7D%7D%20%5Cright.)
=> ![W_c = nRT [ln(V_f) - ln(V_o)]](https://tex.z-dn.net/?f=W_c%20%3D%20nRT%20%5Bln%28V_f%29%20-%20ln%28V_o%29%5D)
=> 
From the question 
=> 
at initial state
<span>Assume: neglect of the collar dimensions.
Ď_h=(P*r)/t=(5*125)/8=78.125 MPa ,Ď_a=Ď_h/2=39 MPa
τ=(S*Q)/(I*b)=(40*〖10〗^3*π(〖0.125〗^2-〖0.117〗^2 )*121*〖10〗^(-3))/(π/2 (〖0.125〗^4-〖0.117〗^4 )*8*〖10〗^(-3) )=41.277 MPa
@ Point K:
Ď_z=(+M*c)/I=(40*0.6*121*〖10〗^(-3))/(8.914*〖10〗^(-5) )=32.6 MPa
Using Mohr Circle:
Ď_max=(Ď_h+Ď_a)/2+âš(Ď„^2+((Ď_h-Ď_a)/2)^2 )
Ď_max=104.2 MPa, Ď„_max=45.62 MPa</span>
Answer:
0.4
Explanation:
A concave lens is a diverging lens, so it will always have a negative focal length. Image distance is always negative for a concave lens because it forms virtual images.
From the lens formula;
1/f = 1/u+ 1/v
- 1/2 = 1/3 - 1/v
1/v = 1/3 + 1/2
v= 6/5
v= 1.2 cm
Magnification = image distance/object distance
Magnification = 1.2cm/3cm
Magnification = 0.4
Gravity
Hope this helps:)
Answer:
Protons , neutrons and elections
