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mars1129 [50]
3 years ago
9

In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?

Chemistry
1 answer:
Oksanka [162]3 years ago
8 0

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In H_2O , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in Cl^- is -1. On product side, the oxidation number of hydrogen in H_2 is zero and in OH^- the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in Cl_2 is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

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Answer:

Because CLEARLY, each mole of glucose, C6H12O6 contains 6⋅mol oxygen atoms.

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3 years ago
Determine the volume in liters occupied by 22.6 g of I2 gas at STP.
AleksandrR [38]

 The volume in liters  occupied  by 22.6 g  of I₂  gas  at STP  is  1.99 L (answer A)

 <u><em>calculation</em></u>

Step: find the  moles of I₂

moles= mass÷  molar mass

from  periodic table the  molar mass  of I₂  is  253.8 g/mol

moles = 22.6 g÷253.8 g/mol =0.089 moles

Step 2:find the volume  of I₂  at STP

At STP  1  moles =22.4 L

         0.089 moles= ? L

<em>by cross  multiplication</em>

={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L


6 0
3 years ago
We can change a gas to liquid by the temperature and the pressure. NextReset
USPshnik [31]
We can change a gas to a liquid by INCREASING the temperature and DECREASING the pressure
7 0
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Read 2 more answers
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

7 0
3 years ago
A strong acid can also be described as a very weak .
faltersainse [42]
I guess is weak alkaline. when the substance is more acidic, there will be less alkalinity
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