PH = -log([H+])
[H+] = 10^(-pH)
[H+] = 10^(-8.78) = 1.65*10^-9
[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.
[OH-] = Kw/[H+] = (1.0*10^-14)/(1.65*10^-9) = 6.06*10^-6
The concentration of OH- ions is 6.1*10^-6 M.
Answer:
answer = 22.5m
Explanation:
using

s= (0²-21²)/2(-9.8)
s= -441/19.6
s= 22.5m
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The answer should be C
The reason for this is because:
There are 2 "I" on the right side of the equation but only 1 on the left. This means you need to add a 2 on the "KI" to get two "I".
But now there are 2 "K" on the left side and only 1 on the right, meaning you need to add a 2 to the "KCL". This makes it balanced
Answer : The boiling point of water increases, 
Solution : Given,
Moles of solute (sugar) = 4 moles
Mass of solvent (water) = 1 Kg

i = 1 for sugar
Formula used :

Where,
= elevation in boiling point
= elevation constant
m = molality
= moles of solute (sugar)
= mass of solvent (water)
i = van't Hoff factor
Now put all the given values in this formula, we get the elevation in boiling point of water.

Therefore, the elevation in boiling point of water is 