Answer:
this is a linear function
Step-by-step explanation:
y = a + bx
in this case:
y = 800 - 114.29x
where:
y = accumulated depreciation
x = number of years
year accumulated
(x) depreciation (y)
0 0
1 114.29
2 228.58
3 342.87
4 457.16
5 571.45
6 685.74
7 800
10 times 0.84 is 8.4 or 8.40 is completely fine as well.
Should be chosen the bigger propability
0,6>0,4
Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is
Standard deviation of Eskimo dogs is
The range of weights would 99.7% of the dogs have,





Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.