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viva [34]
3 years ago
15

Which of these are features of the quantum mechanical model of the atom but not of the Bohr

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

Electrons treated as waves

Explanation:

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What would be the pH of an H2SO4 solution if the [H+] = 4.58 x 10-5 moles/liter?
Ghella [55]

Answer: pH of an H_2SO_4 solution is 4.34

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

H_2SO_4\rightarrow 2H^++SO_4^{2-}

Putting in the values:

pH=-\log[4.58\times 10^{-5}]

pH=4.34

Thus pH of an H_2SO_4 solution if the [H^+] is 4.58\times 10^{-5}] is 4.34

4 0
3 years ago
Write the chemical equation for the reaction of Fe(II) ion (Fe2 ) with phenanthroline. (Use the abbreviation phen for the phenan
miskamm [114]

Answer:

[Fe(phen)3]2+    Reactants  Fe+2 clear phen white solid   product orange red

mol ratios 1;1 OF fE

Explanation:

8 0
3 years ago
All chemical reactions have a conservation of(1) mass, only(2) mass and charge, only(3) charge and energy, only(4) mass, charge,
Semenov [28]
All chemical reactions have a conversation of mass and energy. 

Because:- There are only two laws for conversation in a chemical reaction. The conversation of mass, no mass can be created nor destroyed. Also, the law of conversation of mass states that no energy can be created nor destroyed in a chemical reaction. The charge can obviously change because they can bond and change charges. 
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WILL GIVE BRANLIEST TO WHOEVER ANSWERS THIS QUESTION>>> How many valence electrons does NaHCo3 have?
nydimaria [60]

Answer:

NaHCO3

Na = 1

H = 1

C = 4

Explanation:

5 0
3 years ago
A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of
Georgia [21]

NaOH reacts with CH3COOH in 1:1 molar ratio to produce CH3COONa 

NaOH + CH3COOH → CH3COONa + H2O 

Mol CH3COOH in 52.0mL of 0.35M solution = 52.0/1000*0.35 = 0.0182 mol CH3COOH 

Mol NaOH in 19.0mL of 0.40M solution = 19.0/1000*0.40 = 0.0076 mol NaOH 

These will react to produce 0.0076 mol CH3COONa and there will be 0.0182 - 0.0076 = 0.0106 mol CH3COOH remaining in solution unreacted . Total volume of solution = 52.0+19.0 = 71mL or 0.071L 

Molarity of CH3COOH = 0.0106/0.071 = 0.1493M 

CH3COONa = 0.0076 / 0.071 = 0.1070M 

pKa acetic acid = - log Ka = -log 1.8*10^-5 = 4.74. 

pH using Henderson - Hasselbalch equation: 

pH = pKa + log ([salt]/[acid]) 

pH = 4.74 + log ( 0.1070/0.1493) 

pH = 4.74 + log 0.717 

pH = 4.74 + (-0.14) 

pH = 4.60.

7 0
3 years ago
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