The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm
<h3>
What is Mole ?</h3>
A mole is a very important unit of measurement that chemists use.
A mole of something means you have 6.023 x 10 ²³ of that thing.
- For 2.15 mol of hydrogen sulphide (H₂S) :
1 mole hydrogen sulphide (H₂S) = 34.08088 grams
Therefore,
2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol
= 73.272 gm
- For 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) ;
1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams
Therefore,
3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol
= 1.82 gm
Hence,The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm
Learn more about mole here ;
brainly.com/question/21323029
#SPJ1
Answer:
that is why co2 is in the power of 2ik
Answer is: the average atomic mass is 232.
ω₁ = 20% ÷ 100%.
ω₁ = 0.20.
ω₂ = 80% ÷ 100%.
ω₂ = 0.80.
Ar₁ = 120 (number of protons) + 120 (number of neutrons).
Ar₁ = 240.
Ar₂ = 120 + 110
.
Ar₂ = 230.
Average atomic mass of atoms of bolognium =
Ar₁ · ω₁ + Ar₂ · ω₂.
Average atomic mass of atoms of bolognium = 240 · 0.2 + 230 · 0.8.
Average atomic mass of atoms of bolognium = 48 + 184.
Average atomic mass of atoms of bolognium = 232.
