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miss Akunina [59]
3 years ago
15

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. Cac

, (s)+2H20(I) =C,H,($) + Ca(OH),(s) 6C,H, ()+300,() + 4H2O(g) =SCH,CHCO,H (8) The net reaction is: 6 Cac,(s) +16H20 (1)+300, 6) = 6Ca(OH)($)+5CH,CHCO,H() K Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K, and Ky. If you need to include any physical constant be sure you use their standard symbols, which you'll find in the ALEKS Calculator. K-1 x 5 ?
Chemistry
1 answer:
Tanya [424]3 years ago
4 0

Answer:

The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky

Explanation:

we have the following balanced reaction:

CaC2 + 2H2O = C2H2 + Ca(OH)2

the value of K for this reaction will be equal to:

K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)

if we multiply the reaction by the value of 6, we have:

6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2

Again, the value of K for this reaction will be equal to:

K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6

For the second reaction:

6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H

The value of K for this reaction:

K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)

we also have:

K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)

Thus:

K1 = K^6 * Ky

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Boyle law is a gas law stating the pressure and the volume of a gas have an inverse relationship when held at constant temperature.

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3 years ago
Using Le Chatelier’s principle, predict which equilibrium system below decrease the concentration of the reactant (H2CO3) as a r
seropon [69]

Answer:

The correct answer is c add more HCO3- by adding NaHCO3.

Explanation:

The reaction mentioned in the question is carried out by bicarbonate buffer system of our body to maintain the normal acid  base balance.

         Now concentration of the reactant (H2C03) is decreased then NaHCO3 should be added which undergo breakdown to release bicarbonate ions(HCO3-).

        The released bicarbonate ions then reacts with H+ to form Carbonic acid(H2CO3).Thus homeostasis of H2CO3 is maintained.

4 0
3 years ago
Read 2 more answers
Calculate the number of Cl atoms that are in 1.1 x 10^-21 moles of Cl atoms.
Margarita [4]

According to Avogadro's number there are 62.53 atoms of chlorine in 1.1x 10^-21 moles of Cl atoms.

<h3>What is Avogadro's number?</h3>

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number or number of moles×Avogadro's number.

ON substitution in above formula number of atoms=1.1×10²¹×6.023×10²³=62.53 atoms

Thus, there are 62.53 chlorine  atoms in 1.1x 10^-21 moles of Cl atoms.

Learn more about Avogadro's number,here:

brainly.com/question/11907018

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6 0
1 year ago
Which type of fat is a solid at room temperature and does not have double bonds between carbon
melamori03 [73]

Answer:

Saturated Fats

Explanation:

Saturated fats are all of the above.

Also, Saturated fat is very unhealthy. Only consume it in small amounts.

7 0
3 years ago
Read 2 more answers
In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
3 years ago
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