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miss Akunina [59]
2 years ago
15

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. Cac

, (s)+2H20(I) =C,H,($) + Ca(OH),(s) 6C,H, ()+300,() + 4H2O(g) =SCH,CHCO,H (8) The net reaction is: 6 Cac,(s) +16H20 (1)+300, 6) = 6Ca(OH)($)+5CH,CHCO,H() K Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K, and Ky. If you need to include any physical constant be sure you use their standard symbols, which you'll find in the ALEKS Calculator. K-1 x 5 ?
Chemistry
1 answer:
Tanya [424]2 years ago
4 0

Answer:

The equation that gives the overall equilibrium in terms of the equilibrium constants K and Ky is K1 = K^6 * Ky

Explanation:

we have the following balanced reaction:

CaC2 + 2H2O = C2H2 + Ca(OH)2

the value of K for this reaction will be equal to:

K = ([C2H2] * [Ca(OH)2])/([CaC2] * [H2O]^2)

if we multiply the reaction by the value of 6, we have:

6CaC2 + 12H2O = 6C2H2 + 6Ca(OH)2

Again, the value of K for this reaction will be equal to:

K,´ = ([C2H2] ^6 * [Ca(OH)2]^6)/([CaC2]^6 * [H2O]^12) = K^6

For the second reaction:

6C2H2 + 3CO2 + 4H2O = 5CH2CHCO2H

The value of K for this reaction:

K2 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^4)

we also have:

K1 = ([CH2CHCO2H]^5)/([C2H2]^6 * [CO2]^3 * [H2O]^16)

Thus:

K1 = K^6 * Ky

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Approximate molecular masses:
Molecular mass of C = 12
Molecular mass of H = 1

Let n = moles required for CH₂.
Then
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n(12 + 2*1) = 98
14n = 98
n = 7

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