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Nataliya [291]
3 years ago
14

If I have 3 liters of solute, and 4 liters of solvent how many liters in solution do I have?

Chemistry
1 answer:
yaroslaw [1]3 years ago
5 0

Answer:

seven litres i

i.e three litres plus four litres

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Which of the following lists the correct symbol for the ion that tin forms when it loses 2 electrons, the correct classification
ser-zykov [4K]

Answer:

\huge\boxed{\sf Option \ A}

Explanation:

The symbol for TIN is Sn.

When Sn loses 2 electrons, it gets a double positive charge ( +2 ) and becomes \sf Sn ^{+2}.

It becomes a cation.

The name of Ion is Tin ( II ) Ion.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
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An 80 kg long jumper in flight accelerates at a rate of 10 m/s^2. What is the force of the long jumper
Katarina [22]

Answer:

F = 800 N

Explanation:

Given data:

Mass = 80 Kg

Acceleration = 10 m/s²

Force = ?

Solution:

Formula:

<em>F = m × a </em>

F = force

m = mass

a = acceleration

Now we will put the values in formula:

<em>F = m × a </em>

F = 80 kg <em>× </em>10 m/s²

F = 800 kg.m/s²

kg.m/s² = N

F = 800 N

6 0
3 years ago
How are the various features of the Earth created by the Earth’s inner processes?
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8 0
3 years ago
300 moles of sodium nitrite are needed for a reaction. the solution is 0.450 m. how many ml are needed?
miv72 [106K]

Answer:

\boxed{\text{667 000 mL}}

Explanation:

\text{Molar concentration} = \dfrac{\text{moles}}{\text{litres}}\\\\c = \dfrac{n}{v}

Data:

c = 0.450 mol·L⁻¹

n = 300 mol

Calculation:

\begin{array}{rcl}0.450 & = & \dfrac{300}{V}\\\\0.450V& = & 300\\\\V & = & \dfrac{300}{0.450}\\\\V & = & \text{667 L} =\textbf{667 000 mL}\end{array}\\\text{The volume of solution needed is }\boxed{\textbf{667 000 mL}}

4 0
3 years ago
How much heat is required to raise the temperature of a 6.21 g sample of iron from 25.0 oC to 79.8 oC?
telo118 [61]

Answer:

151.1J

Explanation:

Given parameters:

Mass of iron  = 6.21g

Initial temperature of iron  = 25°C

Final temperature of iron  = 79.8°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat require to cause this temperature can be determined using the expression below;

    H  = m c (T₂ - T₁)

H is the amount of heat

m is the mass

c is the specific heat capacity

T is the temperature

    Specific heat capacity of iron 0.444J/g°C

Insert the parameters and solve;

     H  = 6.21 x 0.444 x (79.8 - 25)

     H   = 151.1J

5 0
3 years ago
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