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Nataliya [291]
3 years ago
14

If I have 3 liters of solute, and 4 liters of solvent how many liters in solution do I have?

Chemistry
1 answer:
yaroslaw [1]3 years ago
5 0

Answer:

seven litres i

i.e three litres plus four litres

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A 5.0 L sample of gas at 300. K is heated to 600. K. What will the new volume of the gas be?
Ainat [17]

Answer:

V_2=10L

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

\frac{V_2}{T_2} =\frac{V_1}{T_1}

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L

Regards!

4 0
3 years ago
What is the pH of the solution formed when 25 mL of 0.173 M NaOH is added to 35 mL of 0.342 M HCl?
Ugo [173]

Answer:

0.89

Explanation:

You are mixing an acid and a base, so there will be a neutralization reaction.

One of the reactants will be in excess, so we must determine its concentration and then calculate the pH.

<em>Moles of NaOH </em>

Moles of NaOH = 25 × 0.173

Moles of NaOH = 4.32 mmol

===============

<em>Moles of HCl </em>

Moles of HCl = 35 × 0.342

Moles of HCl = 12.0 mmol

===============

<em>Amount of excess reactant </em>

              NaOH + HCl ⟶ NaCl +H₂O

<em>n</em>/mmol:   4.32      12.0

The 4.32 mmol of NaOH reacts completely with 4.32 mmol of HCl.

Excess HCl = 12.0 – 4.32

Excess HCl = 7.6 mmol

===============

<em>Concentration of the excess HCl </em>

Total volume = 25 + 35

Total volume = 60 mL

<em>c </em>= millimoles HCl/millilitres HCl

<em>c</em> = 7.6/60

<em>c</em> = 0.13 mol/L

===============

<em>Calculate the pH </em>

The HCl dissociates completely to hydronium ions, so

[H₃O⁺] = 0.13 mol·L⁻¹

pH = -log[H₃O⁺]

pH = -log0.13

pH = 0.89

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Answer:

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Jamal’s hair is behaving that way because he is in a cold area.
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Which two explanation are based on personal beliefs
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