100cos30° + 80cos120° + 40cos233° + Dx = 0
<span>Dx = -22.53 N </span>
<span>y components: </span>
<span>100sin30° + 80sin120° + 40sin233° + Dy = 0 </span>
<span>Dy = -87.34 N </span>
<span>magnitude of D: </span>
<span>sqrt[(-22.53)² + (-87.34)²] </span>
<span>90.2 N </span>
<span>direction of D: </span>
<span>arctan[(-87.34)/(-22.53)] </span>
<span>75.5° ref, but since Dx and Dy are both negative, we know this vector is in QIV: </span>
<span>360 - 75.5° = 284.5°</span>
Answer:
100 cc
Explanation:
Heat released in cooling human body by t degree
= mass of the body x specific heat of the body x t
Substituting the data given
Heat released by the body
= 70 x 3480 x 1
= 243600 J
Mass of water to be evaporated
= 243600 / latent heat of vaporization of water
= 243600 / 2420000
= .1 kg
= 100 g
volume of water
= mass / density
= 100 / 1
100 cc
1 / 10 litres.
Answer:
=140 cm²
Explanation:
1
____ ×20x 14
2
=1
___ x base × height
is the formula have a gr8 day :)
2
Answer:
Explanation:
Additional information:
<em>The ball has charge </em>
<em>, and the ring has positive charge </em>
<em> distributed uniformly along its circumference. </em>
The electric field at distance 
along the z-axis due to the charged ring is
Therefore, the force on the ball with charge is
and according to Newton's second law
substituting 
we get:
rearranging we get:
Now we use the approximation that
<em>(we use this approximation instead of the original </em>
<em> since </em>
<em>, our assumption still holds )</em>
and get
Now the last equation looks like a Simple Harmonic Equation
where
is the frequency of oscillation. Applying this to our equation we get:
